$$$1 - y^{2}$$$ 关于$$$x$$$的积分
您的输入
求$$$\int \left(1 - y^{2}\right)\, dx$$$。
解答
应用常数法则 $$$\int c\, dx = c x$$$,使用 $$$c=1 - y^{2}$$$:
$${\color{red}{\int{\left(1 - y^{2}\right)d x}}} = {\color{red}{x \left(1 - y^{2}\right)}}$$
因此,
$$\int{\left(1 - y^{2}\right)d x} = x \left(1 - y^{2}\right)$$
加上积分常数:
$$\int{\left(1 - y^{2}\right)d x} = x \left(1 - y^{2}\right)+C$$
答案
$$$\int \left(1 - y^{2}\right)\, dx = x \left(1 - y^{2}\right) + C$$$A
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