Integral of $$$\frac{\sqrt{2}}{2}$$$ with respect to $$$t$$$
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Your Input
Find $$$\int \frac{\sqrt{2}}{2}\, dt$$$.
Solution
Apply the constant rule $$$\int c\, dt = c t$$$ with $$$c=\frac{\sqrt{2}}{2}$$$:
$${\color{red}{\int{\frac{\sqrt{2}}{2} d t}}} = {\color{red}{\left(\frac{\sqrt{2} t}{2}\right)}}$$
Therefore,
$$\int{\frac{\sqrt{2}}{2} d t} = \frac{\sqrt{2} t}{2}$$
Add the constant of integration:
$$\int{\frac{\sqrt{2}}{2} d t} = \frac{\sqrt{2} t}{2}+C$$
Answer
$$$\int \frac{\sqrt{2}}{2}\, dt = \frac{\sqrt{2} t}{2} + C$$$A
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