$$$\frac{1}{\sqrt{u^{2} + 1}}$$$의 적분

$$$\int \frac{1}{\sqrt{u^{2} + 1}}\, du$$$을(를) 구하시오.

$$$\frac{1}{\sqrt{u^{2} + 1}}$$$의 적분은 $$$\int{\frac{1}{\sqrt{u^{2} + 1}} d u} = \operatorname{asinh}{\left(u \right)}$$$:

$${\color{red}{\int{\frac{1}{\sqrt{u^{2} + 1}} d u}}} = {\color{red}{\operatorname{asinh}{\left(u \right)}}}$$

따라서,

$$\int{\frac{1}{\sqrt{u^{2} + 1}} d u} = \operatorname{asinh}{\left(u \right)}$$

적분 상수를 추가하세요:

$$\int{\frac{1}{\sqrt{u^{2} + 1}} d u} = \operatorname{asinh}{\left(u \right)}+C$$

$$$\int \frac{1}{\sqrt{u^{2} + 1}}\, du = \operatorname{asinh}{\left(u \right)} + C$$$A