$$$\frac{1}{\sqrt{1 - y^{2}}}$$$의 적분

$$$\int \frac{1}{\sqrt{1 - y^{2}}}\, dy$$$을(를) 구하시오.

$$$\frac{1}{\sqrt{1 - y^{2}}}$$$의 적분은 $$$\int{\frac{1}{\sqrt{1 - y^{2}}} d y} = \operatorname{asin}{\left(y \right)}$$$:

$${\color{red}{\int{\frac{1}{\sqrt{1 - y^{2}}} d y}}} = {\color{red}{\operatorname{asin}{\left(y \right)}}}$$

따라서,

$$\int{\frac{1}{\sqrt{1 - y^{2}}} d y} = \operatorname{asin}{\left(y \right)}$$

적분 상수를 추가하세요:

$$\int{\frac{1}{\sqrt{1 - y^{2}}} d y} = \operatorname{asin}{\left(y \right)}+C$$

$$$\int \frac{1}{\sqrt{1 - y^{2}}}\, dy = \operatorname{asin}{\left(y \right)} + C$$$A