Integral of $$$\frac{_1}{x}$$$ with respect to $$$e$$$
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Your Input
Find $$$\int \frac{_1}{x}\, de$$$.
Solution
Apply the constant rule $$$\int c\, de = c e$$$ with $$$c=\frac{_1}{x}$$$:
$${\color{red}{\int{\frac{_1}{x} d e}}} = {\color{red}{\frac{_1 e}{x}}}$$
Therefore,
$$\int{\frac{_1}{x} d e} = \frac{_1 e}{x}$$
Add the constant of integration:
$$\int{\frac{_1}{x} d e} = \frac{_1 e}{x}+C$$
Answer
$$$\int \frac{_1}{x}\, de = \frac{_1 e}{x} + C$$$A
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