化簡 $$$\left(\overline{A} \cdot C \cdot D\right) + \left(\overline{A} \cdot \overline{C} \cdot \overline{D}\right)$$$

此計算器將簡化布林運算式 $$$\left(\overline{A} \cdot C \cdot D\right) + \left(\overline{A} \cdot \overline{C} \cdot \overline{D}\right)$$$,並顯示步驟。

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您的輸入

化簡布林運算式 $$$\left(\overline{A} \cdot C \cdot D\right) + \left(\overline{A} \cdot \overline{C} \cdot \overline{D}\right)$$$

解答

改寫:

$${\color{red}\left(\overline{A} \cdot C \cdot D\right) + \left(\overline{A} \cdot \overline{C} \cdot \overline{D}\right)} = {\color{red}\left(\left(C \cdot D\right) + \left(\overline{C} \cdot \overline{D}\right)\right) \cdot \overline{A}}$$

進一步化簡:

$${\color{red}\left(\left(C \cdot D\right) + \left(\overline{C} \cdot \overline{D}\right)\right) \cdot \overline{A}} = {\color{red}\overline{A} \cdot \left(C + \overline{D}\right) \cdot \left(D + \overline{C}\right)}$$

答案

$$$\left(\overline{A} \cdot C \cdot D\right) + \left(\overline{A} \cdot \overline{C} \cdot \overline{D}\right) = \overline{A} \cdot \left(C + \overline{D}\right) \cdot \left(D + \overline{C}\right)$$$


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