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Förenkla $$$\left(\overline{A} \cdot C \cdot D\right) + \left(\overline{A} \cdot \overline{C} \cdot \overline{D}\right)$$$
Relaterad kalkylator: Kalkylator för sanningsvärdestabeller
Din inmatning
Förenkla det booleska uttrycket $$$\left(\overline{A} \cdot C \cdot D\right) + \left(\overline{A} \cdot \overline{C} \cdot \overline{D}\right).$$$
Lösning
Skriv om:
$${\color{red}\left(\overline{A} \cdot C \cdot D\right) + \left(\overline{A} \cdot \overline{C} \cdot \overline{D}\right)} = {\color{red}\left(\left(C \cdot D\right) + \left(\overline{C} \cdot \overline{D}\right)\right) \cdot \overline{A}}$$Förenkla ytterligare:
$${\color{red}\left(\left(C \cdot D\right) + \left(\overline{C} \cdot \overline{D}\right)\right) \cdot \overline{A}} = {\color{red}\overline{A} \cdot \left(C + \overline{D}\right) \cdot \left(D + \overline{C}\right)}$$Svar
$$$\left(\overline{A} \cdot C \cdot D\right) + \left(\overline{A} \cdot \overline{C} \cdot \overline{D}\right) = \overline{A} \cdot \left(C + \overline{D}\right) \cdot \left(D + \overline{C}\right)$$$
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