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$$$\left[\begin{array}{c}- a^{2} g^{2} h^{2} m^{2} n^{2} r^{2} s^{2} t^{4} e^{2 e i n o r s^{2}} - \lambda\end{array}\right]$$$ 的行列式
相关计算器: 代数余子式矩阵计算器
您的输入
计算 $$$\left|\begin{array}{c}- a^{2} g^{2} h^{2} m^{2} n^{2} r^{2} s^{2} t^{4} e^{2 e i n o r s^{2}} - \lambda\end{array}\right|$$$。
解答
1x1 矩阵的行列式是 $$$\left|\begin{array}{c}a\end{array}\right| = a$$$。
$$$\left|\begin{array}{c}- a^{2} g^{2} h^{2} m^{2} n^{2} r^{2} s^{2} t^{4} e^{2 e i n o r s^{2}} - \lambda\end{array}\right| = - a^{2} g^{2} h^{2} m^{2} n^{2} r^{2} s^{2} t^{4} e^{2 e i n o r s^{2}} - \lambda$$$
答案
$$$\left|\begin{array}{c}- a^{2} g^{2} h^{2} m^{2} n^{2} r^{2} s^{2} t^{4} e^{2 e i n o r s^{2}} - \lambda\end{array}\right| = - a^{2} g^{2} h^{2} m^{2} n^{2} r^{2} s^{2} t^{4} e^{2 e i n o r s^{2}} - \lambda$$$A