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$$$\frac{1}{a^{2} u}$$$ 关于$$$x$$$的积分
您的输入
求$$$\int \frac{1}{a^{2} u}\, dx$$$。
解答
应用常数法则 $$$\int c\, dx = c x$$$，使用 $$$c=\frac{1}{a^{2} u}$$$：
$${\color{red}{\int{\frac{1}{a^{2} u} d x}}} = {\color{red}{\frac{x}{a^{2} u}}}$$
因此，
$$\int{\frac{1}{a^{2} u} d x} = \frac{x}{a^{2} u}$$
加上积分常数：
$$\int{\frac{1}{a^{2} u} d x} = \frac{x}{a^{2} u}+C$$
答案
$$$\int \frac{1}{a^{2} u}\, dx = \frac{x}{a^{2} u} + C$$$A
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