Integral of $$$\frac{1}{a^{2} u}$$$ with respect to $$$x$$$
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Your Input
Find $$$\int \frac{1}{a^{2} u}\, dx$$$.
Solution
Apply the constant rule $$$\int c\, dx = c x$$$ with $$$c=\frac{1}{a^{2} u}$$$:
$${\color{red}{\int{\frac{1}{a^{2} u} d x}}} = {\color{red}{\frac{x}{a^{2} u}}}$$
Therefore,
$$\int{\frac{1}{a^{2} u} d x} = \frac{x}{a^{2} u}$$
Add the constant of integration:
$$\int{\frac{1}{a^{2} u} d x} = \frac{x}{a^{2} u}+C$$
Answer
$$$\int \frac{1}{a^{2} u}\, dx = \frac{x}{a^{2} u} + C$$$A
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