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$$$x^{7 x}$$$的导数
您的输入
求$$$\frac{d}{dx} \left(x^{7 x}\right)$$$。
解答
设$$$H{\left(x \right)} = x^{7 x}$$$。
对等式两边取对数：$$$\ln\left(H{\left(x \right)}\right) = \ln\left(x^{7 x}\right)$$$。
利用对数的性质改写等式右边：$$$\ln\left(H{\left(x \right)}\right) = 7 x \ln\left(x\right)$$$。
分别对方程两边求导：$$$\frac{d}{dx} \left(\ln\left(H{\left(x \right)}\right)\right) = \frac{d}{dx} \left(7 x \ln\left(x\right)\right)$$$。
对方程的左边求导。
函数$$$\ln\left(H{\left(x \right)}\right)$$$是两个函数$$$f{\left(u \right)} = \ln\left(u\right)$$$和$$$g{\left(x \right)} = H{\left(x \right)}$$$的复合$$$f{\left(g{\left(x \right)} \right)}$$$。
应用链式法则 $$$\frac{d}{dx} \left(f{\left(g{\left(x \right)} \right)}\right) = \frac{d}{du} \left(f{\left(u \right)}\right) \frac{d}{dx} \left(g{\left(x \right)}\right)$$$：
$${\color{red}\left(\frac{d}{dx} \left(\ln\left(H{\left(x \right)}\right)\right)\right)} = {\color{red}\left(\frac{d}{du} \left(\ln\left(u\right)\right) \frac{d}{dx} \left(H{\left(x \right)}\right)\right)}$$自然对数的导数为 $$$\frac{d}{du} \left(\ln\left(u\right)\right) = \frac{1}{u}$$$：
$${\color{red}\left(\frac{d}{du} \left(\ln\left(u\right)\right)\right)} \frac{d}{dx} \left(H{\left(x \right)}\right) = {\color{red}\left(\frac{1}{u}\right)} \frac{d}{dx} \left(H{\left(x \right)}\right)$$返回到原变量：
$$\frac{\frac{d}{dx} \left(H{\left(x \right)}\right)}{{\color{red}\left(u\right)}} = \frac{\frac{d}{dx} \left(H{\left(x \right)}\right)}{{\color{red}\left(H{\left(x \right)}\right)}}$$因此，$$$\frac{d}{dx} \left(\ln\left(H{\left(x \right)}\right)\right) = \frac{\frac{d}{dx} \left(H{\left(x \right)}\right)}{H{\left(x \right)}}$$$。
对等式右边求导。
对 $$$c = 7$$$ 和 $$$f{\left(x \right)} = x \ln\left(x\right)$$$ 应用常数倍法则 $$$\frac{d}{dx} \left(c f{\left(x \right)}\right) = c \frac{d}{dx} \left(f{\left(x \right)}\right)$$$：
$${\color{red}\left(\frac{d}{dx} \left(7 x \ln\left(x\right)\right)\right)} = {\color{red}\left(7 \frac{d}{dx} \left(x \ln\left(x\right)\right)\right)}$$对 $$$f{\left(x \right)} = x$$$ 和 $$$g{\left(x \right)} = \ln\left(x\right)$$$ 应用乘积法则 $$$\frac{d}{dx} \left(f{\left(x \right)} g{\left(x \right)}\right) = \frac{d}{dx} \left(f{\left(x \right)}\right) g{\left(x \right)} + f{\left(x \right)} \frac{d}{dx} \left(g{\left(x \right)}\right)$$$:
$$7 {\color{red}\left(\frac{d}{dx} \left(x \ln\left(x\right)\right)\right)} = 7 {\color{red}\left(\frac{d}{dx} \left(x\right) \ln\left(x\right) + x \frac{d}{dx} \left(\ln\left(x\right)\right)\right)}$$自然对数的导数为 $$$\frac{d}{dx} \left(\ln\left(x\right)\right) = \frac{1}{x}$$$：
$$7 x {\color{red}\left(\frac{d}{dx} \left(\ln\left(x\right)\right)\right)} + 7 \ln\left(x\right) \frac{d}{dx} \left(x\right) = 7 x {\color{red}\left(\frac{1}{x}\right)} + 7 \ln\left(x\right) \frac{d}{dx} \left(x\right)$$应用幂法则 $$$\frac{d}{dx} \left(x^{n}\right) = n x^{n - 1}$$$，取 $$$n = 1$$$，也就是说，$$$\frac{d}{dx} \left(x\right) = 1$$$：
$$7 \ln\left(x\right) {\color{red}\left(\frac{d}{dx} \left(x\right)\right)} + 7 = 7 \ln\left(x\right) {\color{red}\left(1\right)} + 7$$因此，$$$\frac{d}{dx} \left(7 x \ln\left(x\right)\right) = 7 \ln\left(x\right) + 7$$$。
因此，$$$\frac{\frac{d}{dx} \left(H{\left(x \right)}\right)}{H{\left(x \right)}} = 7 \ln\left(x\right) + 7$$$。
因此，$$$\frac{d}{dx} \left(H{\left(x \right)}\right) = \left(7 \ln\left(x\right) + 7\right) H{\left(x \right)} = 7 x^{7 x} \left(\ln\left(x\right) + 1\right)$$$。
答案
$$$\frac{d}{dx} \left(x^{7 x}\right) = 7 x^{7 x} \left(\ln\left(x\right) + 1\right)$$$A