Integral de $$$e^{3 x^{2}}$$$

Encontre $$$\int e^{3 x^{2}}\, dx$$$.

Seja $$$u=\sqrt{3} x$$$.

Então $$$du=\left(\sqrt{3} x\right)^{\prime }dx = \sqrt{3} dx$$$ (veja os passos »), e obtemos $$$dx = \frac{\sqrt{3} du}{3}$$$.

Portanto,

$${\color{red}{\int{e^{3 x^{2}} d x}}} = {\color{red}{\int{\frac{\sqrt{3} e^{u^{2}}}{3} d u}}}$$

Aplique a regra do múltiplo constante $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ usando $$$c=\frac{\sqrt{3}}{3}$$$ e $$$f{\left(u \right)} = e^{u^{2}}$$$:

$${\color{red}{\int{\frac{\sqrt{3} e^{u^{2}}}{3} d u}}} = {\color{red}{\left(\frac{\sqrt{3} \int{e^{u^{2}} d u}}{3}\right)}}$$

Esta integral (Função erro imaginária) não possui forma fechada:

$$\frac{\sqrt{3} {\color{red}{\int{e^{u^{2}} d u}}}}{3} = \frac{\sqrt{3} {\color{red}{\left(\frac{\sqrt{\pi} \operatorname{erfi}{\left(u \right)}}{2}\right)}}}{3}$$

Recorde que $$$u=\sqrt{3} x$$$:

$$\frac{\sqrt{3} \sqrt{\pi} \operatorname{erfi}{\left({\color{red}{u}} \right)}}{6} = \frac{\sqrt{3} \sqrt{\pi} \operatorname{erfi}{\left({\color{red}{\sqrt{3} x}} \right)}}{6}$$

Portanto,

$$\int{e^{3 x^{2}} d x} = \frac{\sqrt{3} \sqrt{\pi} \operatorname{erfi}{\left(\sqrt{3} x \right)}}{6}$$

Adicione a constante de integração:

$$\int{e^{3 x^{2}} d x} = \frac{\sqrt{3} \sqrt{\pi} \operatorname{erfi}{\left(\sqrt{3} x \right)}}{6}+C$$

$$$\int e^{3 x^{2}}\, dx = \frac{\sqrt{3} \sqrt{\pi} \operatorname{erfi}{\left(\sqrt{3} x \right)}}{6} + C$$$A