Calculadora de integrais definidas e impróprias
Calcular integrais definidas e impróprias passo a passo
A calculadora tentará calcular a integral definida (ou seja, com limites), inclusive imprópria, com as etapas mostradas.
Solution
Your input: calculate $$$\int_{0}^{2}\left( 3 x^{2} + x - 1 \right)dx$$$
First, calculate the corresponding indefinite integral: $$$\int{\left(3 x^{2} + x - 1\right)d x}=x^{3} + \frac{x^{2}}{2} - x$$$ (for steps, see indefinite integral calculator)
According to the Fundamental Theorem of Calculus, $$$\int_a^b F(x) dx=f(b)-f(a)$$$, so just evaluate the integral at the endpoints, and that's the answer.
$$$\left(x^{3} + \frac{x^{2}}{2} - x\right)|_{\left(x=2\right)}=8$$$
$$$\left(x^{3} + \frac{x^{2}}{2} - x\right)|_{\left(x=0\right)}=0$$$
$$$\int_{0}^{2}\left( 3 x^{2} + x - 1 \right)dx=\left(x^{3} + \frac{x^{2}}{2} - x\right)|_{\left(x=2\right)}-\left(x^{3} + \frac{x^{2}}{2} - x\right)|_{\left(x=0\right)}=8$$$
Answer: $$$\int_{0}^{2}\left( 3 x^{2} + x - 1 \right)dx=8$$$