Integral de $$$- \sqrt[3]{3} \sqrt[3]{x} - 1$$$
Calculadora relacionada: Calculadora de Integrais Definidas e Impróprias
Sua entrada
Encontre $$$\int \left(- \sqrt[3]{3} \sqrt[3]{x} - 1\right)\, dx$$$.
Solução
Integre termo a termo:
$${\color{red}{\int{\left(- \sqrt[3]{3} \sqrt[3]{x} - 1\right)d x}}} = {\color{red}{\left(- \int{1 d x} - \int{\sqrt[3]{3} \sqrt[3]{x} d x}\right)}}$$
Aplique a regra da constante $$$\int c\, dx = c x$$$ usando $$$c=1$$$:
$$- \int{\sqrt[3]{3} \sqrt[3]{x} d x} - {\color{red}{\int{1 d x}}} = - \int{\sqrt[3]{3} \sqrt[3]{x} d x} - {\color{red}{x}}$$
Aplique a regra do múltiplo constante $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ usando $$$c=\sqrt[3]{3}$$$ e $$$f{\left(x \right)} = \sqrt[3]{x}$$$:
$$- x - {\color{red}{\int{\sqrt[3]{3} \sqrt[3]{x} d x}}} = - x - {\color{red}{\sqrt[3]{3} \int{\sqrt[3]{x} d x}}}$$
Aplique a regra da potência $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=\frac{1}{3}$$$:
$$- x - \sqrt[3]{3} {\color{red}{\int{\sqrt[3]{x} d x}}}=- x - \sqrt[3]{3} {\color{red}{\int{x^{\frac{1}{3}} d x}}}=- x - \sqrt[3]{3} {\color{red}{\frac{x^{\frac{1}{3} + 1}}{\frac{1}{3} + 1}}}=- x - \sqrt[3]{3} {\color{red}{\left(\frac{3 x^{\frac{4}{3}}}{4}\right)}}$$
Portanto,
$$\int{\left(- \sqrt[3]{3} \sqrt[3]{x} - 1\right)d x} = - \frac{3 \sqrt[3]{3} x^{\frac{4}{3}}}{4} - x$$
Adicione a constante de integração:
$$\int{\left(- \sqrt[3]{3} \sqrt[3]{x} - 1\right)d x} = - \frac{3 \sqrt[3]{3} x^{\frac{4}{3}}}{4} - x+C$$
Resposta
$$$\int \left(- \sqrt[3]{3} \sqrt[3]{x} - 1\right)\, dx = \left(- \frac{3 \sqrt[3]{3} x^{\frac{4}{3}}}{4} - x\right) + C$$$A