Integral dari $$$\sqrt{4 - 4 \sin^{2}{\left(x \right)}}$$$
Kalkulator terkait: Kalkulator Integral Tentu dan Tak Wajar
Masukan Anda
Temukan $$$\int \sqrt{4 - 4 \sin^{2}{\left(x \right)}}\, dx$$$.
Solusi
Sederhanakan integran:
$${\color{red}{\int{\sqrt{4 - 4 \sin^{2}{\left(x \right)}} d x}}} = {\color{red}{\int{2 \sqrt{1 - \sin^{2}{\left(x \right)}} d x}}}$$
Terapkan aturan pengali konstanta $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ dengan $$$c=2$$$ dan $$$f{\left(x \right)} = \sqrt{1 - \sin^{2}{\left(x \right)}}$$$:
$${\color{red}{\int{2 \sqrt{1 - \sin^{2}{\left(x \right)}} d x}}} = {\color{red}{\left(2 \int{\sqrt{1 - \sin^{2}{\left(x \right)}} d x}\right)}}$$
Integral ini (Integral eliptik tak lengkap jenis kedua) tidak memiliki bentuk tertutup:
$$2 {\color{red}{\int{\sqrt{1 - \sin^{2}{\left(x \right)}} d x}}} = 2 {\color{red}{E\left(x\middle| 1\right)}}$$
Oleh karena itu,
$$\int{\sqrt{4 - 4 \sin^{2}{\left(x \right)}} d x} = 2 E\left(x\middle| 1\right)$$
Tambahkan konstanta integrasi:
$$\int{\sqrt{4 - 4 \sin^{2}{\left(x \right)}} d x} = 2 E\left(x\middle| 1\right)+C$$
Jawaban
$$$\int \sqrt{4 - 4 \sin^{2}{\left(x \right)}}\, dx = 2 E\left(x\middle| 1\right) + C$$$A