Integral von $$$x^{4} - x^{3}$$$

Bestimme $$$\int \left(x^{4} - x^{3}\right)\, dx$$$.

Gliedweise integrieren:

$${\color{red}{\int{\left(x^{4} - x^{3}\right)d x}}} = {\color{red}{\left(- \int{x^{3} d x} + \int{x^{4} d x}\right)}}$$

Wenden Sie die Potenzregel $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ mit $$$n=4$$$ an:

$$- \int{x^{3} d x} + {\color{red}{\int{x^{4} d x}}}=- \int{x^{3} d x} + {\color{red}{\frac{x^{1 + 4}}{1 + 4}}}=- \int{x^{3} d x} + {\color{red}{\left(\frac{x^{5}}{5}\right)}}$$

Wenden Sie die Potenzregel $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ mit $$$n=3$$$ an:

$$\frac{x^{5}}{5} - {\color{red}{\int{x^{3} d x}}}=\frac{x^{5}}{5} - {\color{red}{\frac{x^{1 + 3}}{1 + 3}}}=\frac{x^{5}}{5} - {\color{red}{\left(\frac{x^{4}}{4}\right)}}$$

Daher,

$$\int{\left(x^{4} - x^{3}\right)d x} = \frac{x^{5}}{5} - \frac{x^{4}}{4}$$

Vereinfachen:

$$\int{\left(x^{4} - x^{3}\right)d x} = \frac{x^{4} \left(4 x - 5\right)}{20}$$

Fügen Sie die Integrationskonstante hinzu:

$$\int{\left(x^{4} - x^{3}\right)d x} = \frac{x^{4} \left(4 x - 5\right)}{20}+C$$

$$$\int \left(x^{4} - x^{3}\right)\, dx = \frac{x^{4} \left(4 x - 5\right)}{20} + C$$$A