Ableitung von $$$\sec^{3}{\left(x \right)}$$$
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Ihre Eingabe
Bestimme $$$\frac{d}{dx} \left(\sec^{3}{\left(x \right)}\right)$$$.
Lösung
Die Funktion $$$\sec^{3}{\left(x \right)}$$$ ist die Komposition $$$f{\left(g{\left(x \right)} \right)}$$$ der beiden Funktionen $$$f{\left(u \right)} = u^{3}$$$ und $$$g{\left(x \right)} = \sec{\left(x \right)}$$$.
Wende die Kettenregel $$$\frac{d}{dx} \left(f{\left(g{\left(x \right)} \right)}\right) = \frac{d}{du} \left(f{\left(u \right)}\right) \frac{d}{dx} \left(g{\left(x \right)}\right)$$$ an:
$${\color{red}\left(\frac{d}{dx} \left(\sec^{3}{\left(x \right)}\right)\right)} = {\color{red}\left(\frac{d}{du} \left(u^{3}\right) \frac{d}{dx} \left(\sec{\left(x \right)}\right)\right)}$$Wende die Potenzregel $$$\frac{d}{du} \left(u^{n}\right) = n u^{n - 1}$$$ mit $$$n = 3$$$ an:
$${\color{red}\left(\frac{d}{du} \left(u^{3}\right)\right)} \frac{d}{dx} \left(\sec{\left(x \right)}\right) = {\color{red}\left(3 u^{2}\right)} \frac{d}{dx} \left(\sec{\left(x \right)}\right)$$Zurück zur ursprünglichen Variable:
$$3 {\color{red}\left(u\right)}^{2} \frac{d}{dx} \left(\sec{\left(x \right)}\right) = 3 {\color{red}\left(\sec{\left(x \right)}\right)}^{2} \frac{d}{dx} \left(\sec{\left(x \right)}\right)$$Die Ableitung des Sekans ist $$$\frac{d}{dx} \left(\sec{\left(x \right)}\right) = \tan{\left(x \right)} \sec{\left(x \right)}$$$:
$$3 \sec^{2}{\left(x \right)} {\color{red}\left(\frac{d}{dx} \left(\sec{\left(x \right)}\right)\right)} = 3 \sec^{2}{\left(x \right)} {\color{red}\left(\tan{\left(x \right)} \sec{\left(x \right)}\right)}$$Somit gilt $$$\frac{d}{dx} \left(\sec^{3}{\left(x \right)}\right) = 3 \tan{\left(x \right)} \sec^{3}{\left(x \right)}$$$.
Antwort
$$$\frac{d}{dx} \left(\sec^{3}{\left(x \right)}\right) = 3 \tan{\left(x \right)} \sec^{3}{\left(x \right)}$$$A