Integral of $$$5 e^{- x^{2}}$$$
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Find $$$\int 5 e^{- x^{2}}\, dx$$$.
Solution
Apply the constant multiple rule $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ with $$$c=5$$$ and $$$f{\left(x \right)} = e^{- x^{2}}$$$:
$${\color{red}{\int{5 e^{- x^{2}} d x}}} = {\color{red}{\left(5 \int{e^{- x^{2}} d x}\right)}}$$
This integral (Error Function) does not have a closed form:
$$5 {\color{red}{\int{e^{- x^{2}} d x}}} = 5 {\color{red}{\left(\frac{\sqrt{\pi} \operatorname{erf}{\left(x \right)}}{2}\right)}}$$
Therefore,
$$\int{5 e^{- x^{2}} d x} = \frac{5 \sqrt{\pi} \operatorname{erf}{\left(x \right)}}{2}$$
Add the constant of integration:
$$\int{5 e^{- x^{2}} d x} = \frac{5 \sqrt{\pi} \operatorname{erf}{\left(x \right)}}{2}+C$$
Answer
$$$\int 5 e^{- x^{2}}\, dx = \frac{5 \sqrt{\pi} \operatorname{erf}{\left(x \right)}}{2} + C$$$A