Integral de $$$\frac{1}{s^{2}}$$$

Encontre $$$\int \frac{1}{s^{2}}\, ds$$$.

Aplique a regra da potência $$$\int s^{n}\, ds = \frac{s^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ com $$$n=-2$$$:

$${\color{red}{\int{\frac{1}{s^{2}} d s}}}={\color{red}{\int{s^{-2} d s}}}={\color{red}{\frac{s^{-2 + 1}}{-2 + 1}}}={\color{red}{\left(- s^{-1}\right)}}={\color{red}{\left(- \frac{1}{s}\right)}}$$

Portanto,

$$\int{\frac{1}{s^{2}} d s} = - \frac{1}{s}$$

Adicione a constante de integração:

$$\int{\frac{1}{s^{2}} d s} = - \frac{1}{s}+C$$

$$$\int \frac{1}{s^{2}}\, ds = - \frac{1}{s} + C$$$A