Integraal van $$$- x^{5} \left(2 x - 6\right)$$$

Bepaal $$$\int \left(- x^{5} \left(2 x - 6\right)\right)\, dx$$$.

De invoer is herschreven: $$$\int{\left(- x^{5} \left(2 x - 6\right)\right)d x}=\int{x^{5} \left(6 - 2 x\right) d x}$$$.

Vereenvoudig de integraand:

$${\color{red}{\int{x^{5} \left(6 - 2 x\right) d x}}} = {\color{red}{\int{2 x^{5} \left(3 - x\right) d x}}}$$

Pas de constante-veelvoudregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ toe met $$$c=2$$$ en $$$f{\left(x \right)} = x^{5} \left(3 - x\right)$$$:

$${\color{red}{\int{2 x^{5} \left(3 - x\right) d x}}} = {\color{red}{\left(2 \int{x^{5} \left(3 - x\right) d x}\right)}}$$

Expand the expression:

$$2 {\color{red}{\int{x^{5} \left(3 - x\right) d x}}} = 2 {\color{red}{\int{\left(- x^{6} + 3 x^{5}\right)d x}}}$$

Integreer termgewijs:

$$2 {\color{red}{\int{\left(- x^{6} + 3 x^{5}\right)d x}}} = 2 {\color{red}{\left(\int{3 x^{5} d x} - \int{x^{6} d x}\right)}}$$

Pas de machtsregel $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ toe met $$$n=6$$$:

$$2 \int{3 x^{5} d x} - 2 {\color{red}{\int{x^{6} d x}}}=2 \int{3 x^{5} d x} - 2 {\color{red}{\frac{x^{1 + 6}}{1 + 6}}}=2 \int{3 x^{5} d x} - 2 {\color{red}{\left(\frac{x^{7}}{7}\right)}}$$

Pas de constante-veelvoudregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ toe met $$$c=3$$$ en $$$f{\left(x \right)} = x^{5}$$$:

$$- \frac{2 x^{7}}{7} + 2 {\color{red}{\int{3 x^{5} d x}}} = - \frac{2 x^{7}}{7} + 2 {\color{red}{\left(3 \int{x^{5} d x}\right)}}$$

Pas de machtsregel $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ toe met $$$n=5$$$:

$$- \frac{2 x^{7}}{7} + 6 {\color{red}{\int{x^{5} d x}}}=- \frac{2 x^{7}}{7} + 6 {\color{red}{\frac{x^{1 + 5}}{1 + 5}}}=- \frac{2 x^{7}}{7} + 6 {\color{red}{\left(\frac{x^{6}}{6}\right)}}$$

Dus,

$$\int{x^{5} \left(6 - 2 x\right) d x} = - \frac{2 x^{7}}{7} + x^{6}$$

Vereenvoudig:

$$\int{x^{5} \left(6 - 2 x\right) d x} = \frac{x^{6} \left(7 - 2 x\right)}{7}$$

Voeg de integratieconstante toe:

$$\int{x^{5} \left(6 - 2 x\right) d x} = \frac{x^{6} \left(7 - 2 x\right)}{7}+C$$

$$$\int \left(- x^{5} \left(2 x - 6\right)\right)\, dx = \frac{x^{6} \left(7 - 2 x\right)}{7} + C$$$A