Integraal van $$$x^{4} \ln\left(2\right)$$$

Bepaal $$$\int x^{4} \ln\left(2\right)\, dx$$$.

Pas de constante-veelvoudregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ toe met $$$c=\ln{\left(2 \right)}$$$ en $$$f{\left(x \right)} = x^{4}$$$:

$${\color{red}{\int{x^{4} \ln{\left(2 \right)} d x}}} = {\color{red}{\ln{\left(2 \right)} \int{x^{4} d x}}}$$

Pas de machtsregel $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ toe met $$$n=4$$$:

$$\ln{\left(2 \right)} {\color{red}{\int{x^{4} d x}}}=\ln{\left(2 \right)} {\color{red}{\frac{x^{1 + 4}}{1 + 4}}}=\ln{\left(2 \right)} {\color{red}{\left(\frac{x^{5}}{5}\right)}}$$

Dus,

$$\int{x^{4} \ln{\left(2 \right)} d x} = \frac{x^{5} \ln{\left(2 \right)}}{5}$$

Voeg de integratieconstante toe:

$$\int{x^{4} \ln{\left(2 \right)} d x} = \frac{x^{5} \ln{\left(2 \right)}}{5}+C$$

$$$\int x^{4} \ln\left(2\right)\, dx = \frac{x^{5} \ln\left(2\right)}{5} + C$$$A