Integral of $$$\frac{1}{y^{2} + 1}$$$
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Your Input
Find $$$\int \frac{1}{y^{2} + 1}\, dy$$$.
Solution
The integral of $$$\frac{1}{y^{2} + 1}$$$ is $$$\int{\frac{1}{y^{2} + 1} d y} = \operatorname{atan}{\left(y \right)}$$$:
$${\color{red}{\int{\frac{1}{y^{2} + 1} d y}}} = {\color{red}{\operatorname{atan}{\left(y \right)}}}$$
Therefore,
$$\int{\frac{1}{y^{2} + 1} d y} = \operatorname{atan}{\left(y \right)}$$
Add the constant of integration:
$$\int{\frac{1}{y^{2} + 1} d y} = \operatorname{atan}{\left(y \right)}+C$$
Answer
$$$\int \frac{1}{y^{2} + 1}\, dy = \operatorname{atan}{\left(y \right)} + C$$$A
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