$$$\frac{x^{2}}{1 - x^{\sqrt{2}}}$$$ 的积分

求$$$\int \frac{x^{2}}{1 - x^{\sqrt{2}}}\, dx$$$。

该积分没有闭式表达式：

$${\color{red}{\int{\frac{x^{2}}{1 - x^{\sqrt{2}}} d x}}} = {\color{red}{\left(\frac{x^{3} {{}_{2}F_{1}\left(\begin{matrix} 1, \frac{3 \sqrt{2}}{2} \\ 1 + \frac{3 \sqrt{2}}{2} \end{matrix}\middle| {x^{\sqrt{2}}} \right)}}{3}\right)}}$$

因此，

$$\int{\frac{x^{2}}{1 - x^{\sqrt{2}}} d x} = \frac{x^{3} {{}_{2}F_{1}\left(\begin{matrix} 1, \frac{3 \sqrt{2}}{2} \\ 1 + \frac{3 \sqrt{2}}{2} \end{matrix}\middle| {x^{\sqrt{2}}} \right)}}{3}$$

化简：

$$\int{\frac{x^{2}}{1 - x^{\sqrt{2}}} d x} = \frac{\sqrt{2} x^{3} \Phi\left(x^{\sqrt{2}}, 1, \frac{3 \sqrt{2}}{2}\right)}{2}$$

加上积分常数：

$$\int{\frac{x^{2}}{1 - x^{\sqrt{2}}} d x} = \frac{\sqrt{2} x^{3} \Phi\left(x^{\sqrt{2}}, 1, \frac{3 \sqrt{2}}{2}\right)}{2}+C$$

$$$\int \frac{x^{2}}{1 - x^{\sqrt{2}}}\, dx = \frac{\sqrt{2} x^{3} \Phi\left(x^{\sqrt{2}}, 1, \frac{3 \sqrt{2}}{2}\right)}{2} + C$$$A