$$$x + \sin{\left(x \right)}$$$の導関数
入力内容
$$$\frac{d}{dx} \left(x + \sin{\left(x \right)}\right)$$$ を求めよ。
解答
和/差の導関数は、導関数の和/差である:
$${\color{red}\left(\frac{d}{dx} \left(x + \sin{\left(x \right)}\right)\right)} = {\color{red}\left(\frac{d}{dx} \left(x\right) + \frac{d}{dx} \left(\sin{\left(x \right)}\right)\right)}$$正弦関数の導関数は$$$\frac{d}{dx} \left(\sin{\left(x \right)}\right) = \cos{\left(x \right)}$$$:
$${\color{red}\left(\frac{d}{dx} \left(\sin{\left(x \right)}\right)\right)} + \frac{d}{dx} \left(x\right) = {\color{red}\left(\cos{\left(x \right)}\right)} + \frac{d}{dx} \left(x\right)$$$$$n = 1$$$ を用いて冪法則 $$$\frac{d}{dx} \left(x^{n}\right) = n x^{n - 1}$$$ を適用すると、すなわち $$$\frac{d}{dx} \left(x\right) = 1$$$:
$$\cos{\left(x \right)} + {\color{red}\left(\frac{d}{dx} \left(x\right)\right)} = \cos{\left(x \right)} + {\color{red}\left(1\right)}$$したがって、$$$\frac{d}{dx} \left(x + \sin{\left(x \right)}\right) = \cos{\left(x \right)} + 1$$$。
解答
$$$\frac{d}{dx} \left(x + \sin{\left(x \right)}\right) = \cos{\left(x \right)} + 1$$$A
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