$$$\sec{\left(\theta \right)}$$$の導関数
入力内容
$$$\frac{d}{d\theta} \left(\sec{\left(\theta \right)}\right)$$$ を求めよ。
解答
正割関数の導関数は$$$\frac{d}{d\theta} \left(\sec{\left(\theta \right)}\right) = \tan{\left(\theta \right)} \sec{\left(\theta \right)}$$$:
$${\color{red}\left(\frac{d}{d\theta} \left(\sec{\left(\theta \right)}\right)\right)} = {\color{red}\left(\tan{\left(\theta \right)} \sec{\left(\theta \right)}\right)}$$したがって、$$$\frac{d}{d\theta} \left(\sec{\left(\theta \right)}\right) = \tan{\left(\theta \right)} \sec{\left(\theta \right)}$$$。
解答
$$$\frac{d}{d\theta} \left(\sec{\left(\theta \right)}\right) = \tan{\left(\theta \right)} \sec{\left(\theta \right)}$$$A
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