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$$$3 u + 4$$$の導関数
入力内容
$$$\frac{d}{du} \left(3 u + 4\right)$$$ を求めよ。
解答
和/差の導関数は、導関数の和/差である:
$${\color{red}\left(\frac{d}{du} \left(3 u + 4\right)\right)} = {\color{red}\left(\frac{d}{du} \left(3 u\right) + \frac{d}{du} \left(4\right)\right)}$$定数の導数は$$$0$$$です:
$${\color{red}\left(\frac{d}{du} \left(4\right)\right)} + \frac{d}{du} \left(3 u\right) = {\color{red}\left(0\right)} + \frac{d}{du} \left(3 u\right)$$定数倍の法則 $$$\frac{d}{du} \left(c f{\left(u \right)}\right) = c \frac{d}{du} \left(f{\left(u \right)}\right)$$$ を $$$c = 3$$$ と $$$f{\left(u \right)} = u$$$ に対して適用します:
$${\color{red}\left(\frac{d}{du} \left(3 u\right)\right)} = {\color{red}\left(3 \frac{d}{du} \left(u\right)\right)}$$$$$n = 1$$$ を用いて冪法則 $$$\frac{d}{du} \left(u^{n}\right) = n u^{n - 1}$$$ を適用すると、すなわち $$$\frac{d}{du} \left(u\right) = 1$$$:
$$3 {\color{red}\left(\frac{d}{du} \left(u\right)\right)} = 3 {\color{red}\left(1\right)}$$したがって、$$$\frac{d}{du} \left(3 u + 4\right) = 3$$$。
解答
$$$\frac{d}{du} \left(3 u + 4\right) = 3$$$A
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