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Integral dari $$$\frac{1}{y^{3}}$$$
Kalkulator terkait: Kalkulator Integral Tentu dan Tak Wajar
Masukan Anda
Temukan $$$\int \frac{1}{y^{3}}\, dy$$$.
Solusi
Terapkan aturan pangkat $$$\int y^{n}\, dy = \frac{y^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ dengan $$$n=-3$$$:
$${\color{red}{\int{\frac{1}{y^{3}} d y}}}={\color{red}{\int{y^{-3} d y}}}={\color{red}{\frac{y^{-3 + 1}}{-3 + 1}}}={\color{red}{\left(- \frac{y^{-2}}{2}\right)}}={\color{red}{\left(- \frac{1}{2 y^{2}}\right)}}$$
Oleh karena itu,
$$\int{\frac{1}{y^{3}} d y} = - \frac{1}{2 y^{2}}$$
Tambahkan konstanta integrasi:
$$\int{\frac{1}{y^{3}} d y} = - \frac{1}{2 y^{2}}+C$$
Jawaban
$$$\int \frac{1}{y^{3}}\, dy = - \frac{1}{2 y^{2}} + C$$$A