Integral de $$$\frac{t^{2}}{14}$$$

Halla $$$\int \frac{t^{2}}{14}\, dt$$$.

Aplica la regla del factor constante $$$\int c f{\left(t \right)}\, dt = c \int f{\left(t \right)}\, dt$$$ con $$$c=\frac{1}{14}$$$ y $$$f{\left(t \right)} = t^{2}$$$:

$${\color{red}{\int{\frac{t^{2}}{14} d t}}} = {\color{red}{\left(\frac{\int{t^{2} d t}}{14}\right)}}$$

Aplica la regla de la potencia $$$\int t^{n}\, dt = \frac{t^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ con $$$n=2$$$:

$$\frac{{\color{red}{\int{t^{2} d t}}}}{14}=\frac{{\color{red}{\frac{t^{1 + 2}}{1 + 2}}}}{14}=\frac{{\color{red}{\left(\frac{t^{3}}{3}\right)}}}{14}$$

Por lo tanto,

$$\int{\frac{t^{2}}{14} d t} = \frac{t^{3}}{42}$$

Añade la constante de integración:

$$\int{\frac{t^{2}}{14} d t} = \frac{t^{3}}{42}+C$$

$$$\int \frac{t^{2}}{14}\, dt = \frac{t^{3}}{42} + C$$$A