Integral von $$$\sin{\left(\frac{\pi x}{4} \right)}$$$

Bestimme $$$\int \sin{\left(\frac{\pi x}{4} \right)}\, dx$$$.

Sei $$$u=\frac{\pi x}{4}$$$.

Dann $$$du=\left(\frac{\pi x}{4}\right)^{\prime }dx = \frac{\pi}{4} dx$$$ (die Schritte sind » zu sehen), und es gilt $$$dx = \frac{4 du}{\pi}$$$.

Somit,

$${\color{red}{\int{\sin{\left(\frac{\pi x}{4} \right)} d x}}} = {\color{red}{\int{\frac{4 \sin{\left(u \right)}}{\pi} d u}}}$$

Wende die Konstantenfaktorregel $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ mit $$$c=\frac{4}{\pi}$$$ und $$$f{\left(u \right)} = \sin{\left(u \right)}$$$ an:

$${\color{red}{\int{\frac{4 \sin{\left(u \right)}}{\pi} d u}}} = {\color{red}{\left(\frac{4 \int{\sin{\left(u \right)} d u}}{\pi}\right)}}$$

Das Integral des Sinus lautet $$$\int{\sin{\left(u \right)} d u} = - \cos{\left(u \right)}$$$:

$$\frac{4 {\color{red}{\int{\sin{\left(u \right)} d u}}}}{\pi} = \frac{4 {\color{red}{\left(- \cos{\left(u \right)}\right)}}}{\pi}$$

Zur Erinnerung: $$$u=\frac{\pi x}{4}$$$:

$$- \frac{4 \cos{\left({\color{red}{u}} \right)}}{\pi} = - \frac{4 \cos{\left({\color{red}{\left(\frac{\pi x}{4}\right)}} \right)}}{\pi}$$

Daher,

$$\int{\sin{\left(\frac{\pi x}{4} \right)} d x} = - \frac{4 \cos{\left(\frac{\pi x}{4} \right)}}{\pi}$$

Fügen Sie die Integrationskonstante hinzu:

$$\int{\sin{\left(\frac{\pi x}{4} \right)} d x} = - \frac{4 \cos{\left(\frac{\pi x}{4} \right)}}{\pi}+C$$

$$$\int \sin{\left(\frac{\pi x}{4} \right)}\, dx = - \frac{4 \cos{\left(\frac{\pi x}{4} \right)}}{\pi} + C$$$A