Integral von $$$e x \cos{\left(x \right)}$$$

Bestimme $$$\int e x \cos{\left(x \right)}\, dx$$$.

Wende die Konstantenfaktorregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ mit $$$c=e$$$ und $$$f{\left(x \right)} = x \cos{\left(x \right)}$$$ an:

$${\color{red}{\int{e x \cos{\left(x \right)} d x}}} = {\color{red}{e \int{x \cos{\left(x \right)} d x}}}$$

Für das Integral $$$\int{x \cos{\left(x \right)} d x}$$$ verwenden Sie die partielle Integration $$$\int \operatorname{u} \operatorname{dv} = \operatorname{u}\operatorname{v} - \int \operatorname{v} \operatorname{du}$$$.

Seien $$$\operatorname{u}=x$$$ und $$$\operatorname{dv}=\cos{\left(x \right)} dx$$$.

Dann gilt $$$\operatorname{du}=\left(x\right)^{\prime }dx=1 dx$$$ (Rechenschritte siehe ») und $$$\operatorname{v}=\int{\cos{\left(x \right)} d x}=\sin{\left(x \right)}$$$ (Rechenschritte siehe »).

Das Integral wird zu

$$e {\color{red}{\int{x \cos{\left(x \right)} d x}}}=e {\color{red}{\left(x \cdot \sin{\left(x \right)}-\int{\sin{\left(x \right)} \cdot 1 d x}\right)}}=e {\color{red}{\left(x \sin{\left(x \right)} - \int{\sin{\left(x \right)} d x}\right)}}$$

Das Integral des Sinus lautet $$$\int{\sin{\left(x \right)} d x} = - \cos{\left(x \right)}$$$:

$$e \left(x \sin{\left(x \right)} - {\color{red}{\int{\sin{\left(x \right)} d x}}}\right) = e \left(x \sin{\left(x \right)} - {\color{red}{\left(- \cos{\left(x \right)}\right)}}\right)$$

Daher,

$$\int{e x \cos{\left(x \right)} d x} = e \left(x \sin{\left(x \right)} + \cos{\left(x \right)}\right)$$

Fügen Sie die Integrationskonstante hinzu:

$$\int{e x \cos{\left(x \right)} d x} = e \left(x \sin{\left(x \right)} + \cos{\left(x \right)}\right)+C$$

$$$\int e x \cos{\left(x \right)}\, dx = e \left(x \sin{\left(x \right)} + \cos{\left(x \right)}\right) + C$$$A