Integral von $$$84 i n t \sin{\left(3 x \right)} \cos{\left(3 x \right)}$$$ nach $$$x$$$

Bestimme $$$\int 84 i n t \sin{\left(3 x \right)} \cos{\left(3 x \right)}\, dx$$$.

Wende die Konstantenfaktorregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ mit $$$c=84 i n t$$$ und $$$f{\left(x \right)} = \sin{\left(3 x \right)} \cos{\left(3 x \right)}$$$ an:

$${\color{red}{\int{84 i n t \sin{\left(3 x \right)} \cos{\left(3 x \right)} d x}}} = {\color{red}{\left(84 i n t \int{\sin{\left(3 x \right)} \cos{\left(3 x \right)} d x}\right)}}$$

Sei $$$u=\sin{\left(3 x \right)}$$$.

Dann $$$du=\left(\sin{\left(3 x \right)}\right)^{\prime }dx = 3 \cos{\left(3 x \right)} dx$$$ (die Schritte sind » zu sehen), und es gilt $$$\cos{\left(3 x \right)} dx = \frac{du}{3}$$$.

Also,

$$84 i n t {\color{red}{\int{\sin{\left(3 x \right)} \cos{\left(3 x \right)} d x}}} = 84 i n t {\color{red}{\int{\frac{u}{3} d u}}}$$

Wende die Konstantenfaktorregel $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ mit $$$c=\frac{1}{3}$$$ und $$$f{\left(u \right)} = u$$$ an:

$$84 i n t {\color{red}{\int{\frac{u}{3} d u}}} = 84 i n t {\color{red}{\left(\frac{\int{u d u}}{3}\right)}}$$

Wenden Sie die Potenzregel $$$\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ mit $$$n=1$$$ an:

$$28 i n t {\color{red}{\int{u d u}}}=28 i n t {\color{red}{\frac{u^{1 + 1}}{1 + 1}}}=28 i n t {\color{red}{\left(\frac{u^{2}}{2}\right)}}$$

Zur Erinnerung: $$$u=\sin{\left(3 x \right)}$$$:

$$14 i n t {\color{red}{u}}^{2} = 14 i n t {\color{red}{\sin{\left(3 x \right)}}}^{2}$$

Daher,

$$\int{84 i n t \sin{\left(3 x \right)} \cos{\left(3 x \right)} d x} = 14 i n t \sin^{2}{\left(3 x \right)}$$

Fügen Sie die Integrationskonstante hinzu:

$$\int{84 i n t \sin{\left(3 x \right)} \cos{\left(3 x \right)} d x} = 14 i n t \sin^{2}{\left(3 x \right)}+C$$

$$$\int 84 i n t \sin{\left(3 x \right)} \cos{\left(3 x \right)}\, dx = 14 i n t \sin^{2}{\left(3 x \right)} + C$$$A