Integral von $$$\frac{68}{r}$$$

Bestimme $$$\int \frac{68}{r}\, dr$$$.

Wende die Konstantenfaktorregel $$$\int c f{\left(r \right)}\, dr = c \int f{\left(r \right)}\, dr$$$ mit $$$c=68$$$ und $$$f{\left(r \right)} = \frac{1}{r}$$$ an:

$${\color{red}{\int{\frac{68}{r} d r}}} = {\color{red}{\left(68 \int{\frac{1}{r} d r}\right)}}$$

Das Integral von $$$\frac{1}{r}$$$ ist $$$\int{\frac{1}{r} d r} = \ln{\left(\left|{r}\right| \right)}$$$:

$$68 {\color{red}{\int{\frac{1}{r} d r}}} = 68 {\color{red}{\ln{\left(\left|{r}\right| \right)}}}$$

Daher,

$$\int{\frac{68}{r} d r} = 68 \ln{\left(\left|{r}\right| \right)}$$

Fügen Sie die Integrationskonstante hinzu:

$$\int{\frac{68}{r} d r} = 68 \ln{\left(\left|{r}\right| \right)}+C$$

$$$\int \frac{68}{r}\, dr = 68 \ln\left(\left|{r}\right|\right) + C$$$A