Integral von $$$36 \cos^{2}{\left(\theta \right)}$$$
Verwandter Rechner: Rechner für bestimmte und uneigentliche Integrale
Ihre Eingabe
Bestimme $$$\int 36 \cos^{2}{\left(\theta \right)}\, d\theta$$$.
Lösung
Wende die Konstantenfaktorregel $$$\int c f{\left(\theta \right)}\, d\theta = c \int f{\left(\theta \right)}\, d\theta$$$ mit $$$c=36$$$ und $$$f{\left(\theta \right)} = \cos^{2}{\left(\theta \right)}$$$ an:
$${\color{red}{\int{36 \cos^{2}{\left(\theta \right)} d \theta}}} = {\color{red}{\left(36 \int{\cos^{2}{\left(\theta \right)} d \theta}\right)}}$$
Wende die Potenzreduktionsformel $$$\cos^{2}{\left(\alpha \right)} = \frac{\cos{\left(2 \alpha \right)}}{2} + \frac{1}{2}$$$ mit $$$\alpha=\theta$$$ an:
$$36 {\color{red}{\int{\cos^{2}{\left(\theta \right)} d \theta}}} = 36 {\color{red}{\int{\left(\frac{\cos{\left(2 \theta \right)}}{2} + \frac{1}{2}\right)d \theta}}}$$
Wende die Konstantenfaktorregel $$$\int c f{\left(\theta \right)}\, d\theta = c \int f{\left(\theta \right)}\, d\theta$$$ mit $$$c=\frac{1}{2}$$$ und $$$f{\left(\theta \right)} = \cos{\left(2 \theta \right)} + 1$$$ an:
$$36 {\color{red}{\int{\left(\frac{\cos{\left(2 \theta \right)}}{2} + \frac{1}{2}\right)d \theta}}} = 36 {\color{red}{\left(\frac{\int{\left(\cos{\left(2 \theta \right)} + 1\right)d \theta}}{2}\right)}}$$
Gliedweise integrieren:
$$18 {\color{red}{\int{\left(\cos{\left(2 \theta \right)} + 1\right)d \theta}}} = 18 {\color{red}{\left(\int{1 d \theta} + \int{\cos{\left(2 \theta \right)} d \theta}\right)}}$$
Wenden Sie die Konstantenregel $$$\int c\, d\theta = c \theta$$$ mit $$$c=1$$$ an:
$$18 \int{\cos{\left(2 \theta \right)} d \theta} + 18 {\color{red}{\int{1 d \theta}}} = 18 \int{\cos{\left(2 \theta \right)} d \theta} + 18 {\color{red}{\theta}}$$
Sei $$$u=2 \theta$$$.
Dann $$$du=\left(2 \theta\right)^{\prime }d\theta = 2 d\theta$$$ (die Schritte sind » zu sehen), und es gilt $$$d\theta = \frac{du}{2}$$$.
Das Integral lässt sich umschreiben als
$$18 \theta + 18 {\color{red}{\int{\cos{\left(2 \theta \right)} d \theta}}} = 18 \theta + 18 {\color{red}{\int{\frac{\cos{\left(u \right)}}{2} d u}}}$$
Wende die Konstantenfaktorregel $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ mit $$$c=\frac{1}{2}$$$ und $$$f{\left(u \right)} = \cos{\left(u \right)}$$$ an:
$$18 \theta + 18 {\color{red}{\int{\frac{\cos{\left(u \right)}}{2} d u}}} = 18 \theta + 18 {\color{red}{\left(\frac{\int{\cos{\left(u \right)} d u}}{2}\right)}}$$
Das Integral des Kosinus ist $$$\int{\cos{\left(u \right)} d u} = \sin{\left(u \right)}$$$:
$$18 \theta + 9 {\color{red}{\int{\cos{\left(u \right)} d u}}} = 18 \theta + 9 {\color{red}{\sin{\left(u \right)}}}$$
Zur Erinnerung: $$$u=2 \theta$$$:
$$18 \theta + 9 \sin{\left({\color{red}{u}} \right)} = 18 \theta + 9 \sin{\left({\color{red}{\left(2 \theta\right)}} \right)}$$
Daher,
$$\int{36 \cos^{2}{\left(\theta \right)} d \theta} = 18 \theta + 9 \sin{\left(2 \theta \right)}$$
Fügen Sie die Integrationskonstante hinzu:
$$\int{36 \cos^{2}{\left(\theta \right)} d \theta} = 18 \theta + 9 \sin{\left(2 \theta \right)}+C$$
Antwort
$$$\int 36 \cos^{2}{\left(\theta \right)}\, d\theta = \left(18 \theta + 9 \sin{\left(2 \theta \right)}\right) + C$$$A