Integral von $$$- 10 \sin{\left(x \right)}$$$

Bestimme $$$\int \left(- 10 \sin{\left(x \right)}\right)\, dx$$$.

Wende die Konstantenfaktorregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ mit $$$c=-10$$$ und $$$f{\left(x \right)} = \sin{\left(x \right)}$$$ an:

$${\color{red}{\int{\left(- 10 \sin{\left(x \right)}\right)d x}}} = {\color{red}{\left(- 10 \int{\sin{\left(x \right)} d x}\right)}}$$

Das Integral des Sinus lautet $$$\int{\sin{\left(x \right)} d x} = - \cos{\left(x \right)}$$$:

$$- 10 {\color{red}{\int{\sin{\left(x \right)} d x}}} = - 10 {\color{red}{\left(- \cos{\left(x \right)}\right)}}$$

Daher,

$$\int{\left(- 10 \sin{\left(x \right)}\right)d x} = 10 \cos{\left(x \right)}$$

Fügen Sie die Integrationskonstante hinzu:

$$\int{\left(- 10 \sin{\left(x \right)}\right)d x} = 10 \cos{\left(x \right)}+C$$

$$$\int \left(- 10 \sin{\left(x \right)}\right)\, dx = 10 \cos{\left(x \right)} + C$$$A