Integral von $$$x \operatorname{acos}{\left(1 - x^{4} \right)}$$$
Verwandter Rechner: Rechner für bestimmte und uneigentliche Integrale
Ihre Eingabe
Bestimme $$$\int x \operatorname{acos}{\left(1 - x^{4} \right)}\, dx$$$.
Lösung
Für das Integral $$$\int{x \operatorname{acos}{\left(1 - x^{4} \right)} d x}$$$ verwenden Sie die partielle Integration $$$\int \operatorname{u} \operatorname{dv} = \operatorname{u}\operatorname{v} - \int \operatorname{v} \operatorname{du}$$$.
Seien $$$\operatorname{u}=\operatorname{acos}{\left(1 - x^{4} \right)}$$$ und $$$\operatorname{dv}=x dx$$$.
Dann gilt $$$\operatorname{du}=\left(\operatorname{acos}{\left(1 - x^{4} \right)}\right)^{\prime }dx=\frac{4 x}{\sqrt{2 - x^{4}}} dx$$$ (Rechenschritte siehe ») und $$$\operatorname{v}=\int{x d x}=\frac{x^{2}}{2}$$$ (Rechenschritte siehe »).
Somit,
$${\color{red}{\int{x \operatorname{acos}{\left(1 - x^{4} \right)} d x}}}={\color{red}{\left(\operatorname{acos}{\left(1 - x^{4} \right)} \cdot \frac{x^{2}}{2}-\int{\frac{x^{2}}{2} \cdot \frac{4 x}{\sqrt{2 - x^{4}}} d x}\right)}}={\color{red}{\left(\frac{x^{2} \operatorname{acos}{\left(1 - x^{4} \right)}}{2} - \int{\frac{2 x^{3}}{\sqrt{2 - x^{4}}} d x}\right)}}$$
Sei $$$u=2 - x^{4}$$$.
Dann $$$du=\left(2 - x^{4}\right)^{\prime }dx = - 4 x^{3} dx$$$ (die Schritte sind » zu sehen), und es gilt $$$x^{3} dx = - \frac{du}{4}$$$.
Daher,
$$\frac{x^{2} \operatorname{acos}{\left(1 - x^{4} \right)}}{2} - {\color{red}{\int{\frac{2 x^{3}}{\sqrt{2 - x^{4}}} d x}}} = \frac{x^{2} \operatorname{acos}{\left(1 - x^{4} \right)}}{2} - {\color{red}{\int{\left(- \frac{1}{2 \sqrt{u}}\right)d u}}}$$
Wende die Konstantenfaktorregel $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ mit $$$c=- \frac{1}{2}$$$ und $$$f{\left(u \right)} = \frac{1}{\sqrt{u}}$$$ an:
$$\frac{x^{2} \operatorname{acos}{\left(1 - x^{4} \right)}}{2} - {\color{red}{\int{\left(- \frac{1}{2 \sqrt{u}}\right)d u}}} = \frac{x^{2} \operatorname{acos}{\left(1 - x^{4} \right)}}{2} - {\color{red}{\left(- \frac{\int{\frac{1}{\sqrt{u}} d u}}{2}\right)}}$$
Wenden Sie die Potenzregel $$$\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ mit $$$n=- \frac{1}{2}$$$ an:
$$\frac{x^{2} \operatorname{acos}{\left(1 - x^{4} \right)}}{2} + \frac{{\color{red}{\int{\frac{1}{\sqrt{u}} d u}}}}{2}=\frac{x^{2} \operatorname{acos}{\left(1 - x^{4} \right)}}{2} + \frac{{\color{red}{\int{u^{- \frac{1}{2}} d u}}}}{2}=\frac{x^{2} \operatorname{acos}{\left(1 - x^{4} \right)}}{2} + \frac{{\color{red}{\frac{u^{- \frac{1}{2} + 1}}{- \frac{1}{2} + 1}}}}{2}=\frac{x^{2} \operatorname{acos}{\left(1 - x^{4} \right)}}{2} + \frac{{\color{red}{\left(2 u^{\frac{1}{2}}\right)}}}{2}=\frac{x^{2} \operatorname{acos}{\left(1 - x^{4} \right)}}{2} + \frac{{\color{red}{\left(2 \sqrt{u}\right)}}}{2}$$
Zur Erinnerung: $$$u=2 - x^{4}$$$:
$$\frac{x^{2} \operatorname{acos}{\left(1 - x^{4} \right)}}{2} + \sqrt{{\color{red}{u}}} = \frac{x^{2} \operatorname{acos}{\left(1 - x^{4} \right)}}{2} + \sqrt{{\color{red}{\left(2 - x^{4}\right)}}}$$
Daher,
$$\int{x \operatorname{acos}{\left(1 - x^{4} \right)} d x} = \frac{x^{2} \operatorname{acos}{\left(1 - x^{4} \right)}}{2} + \sqrt{2 - x^{4}}$$
Fügen Sie die Integrationskonstante hinzu:
$$\int{x \operatorname{acos}{\left(1 - x^{4} \right)} d x} = \frac{x^{2} \operatorname{acos}{\left(1 - x^{4} \right)}}{2} + \sqrt{2 - x^{4}}+C$$
Antwort
$$$\int x \operatorname{acos}{\left(1 - x^{4} \right)}\, dx = \left(\frac{x^{2} \operatorname{acos}{\left(1 - x^{4} \right)}}{2} + \sqrt{2 - x^{4}}\right) + C$$$A