Integral von $$$4 t \sin{\left(c^{2} \right)}$$$ nach $$$t$$$

Bestimme $$$\int 4 t \sin{\left(c^{2} \right)}\, dt$$$.

Wende die Konstantenfaktorregel $$$\int c f{\left(t \right)}\, dt = c \int f{\left(t \right)}\, dt$$$ mit $$$c=4 \sin{\left(c^{2} \right)}$$$ und $$$f{\left(t \right)} = t$$$ an:

$${\color{red}{\int{4 t \sin{\left(c^{2} \right)} d t}}} = {\color{red}{\left(4 \sin{\left(c^{2} \right)} \int{t d t}\right)}}$$

Wenden Sie die Potenzregel $$$\int t^{n}\, dt = \frac{t^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ mit $$$n=1$$$ an:

$$4 \sin{\left(c^{2} \right)} {\color{red}{\int{t d t}}}=4 \sin{\left(c^{2} \right)} {\color{red}{\frac{t^{1 + 1}}{1 + 1}}}=4 \sin{\left(c^{2} \right)} {\color{red}{\left(\frac{t^{2}}{2}\right)}}$$

Daher,

$$\int{4 t \sin{\left(c^{2} \right)} d t} = 2 t^{2} \sin{\left(c^{2} \right)}$$

Fügen Sie die Integrationskonstante hinzu:

$$\int{4 t \sin{\left(c^{2} \right)} d t} = 2 t^{2} \sin{\left(c^{2} \right)}+C$$

$$$\int 4 t \sin{\left(c^{2} \right)}\, dt = 2 t^{2} \sin{\left(c^{2} \right)} + C$$$A