Integral von $$$\frac{\theta \sin{\left(1 \right)}}{4}$$$
Verwandter Rechner: Rechner für bestimmte und uneigentliche Integrale
Ihre Eingabe
Bestimme $$$\int \frac{\theta \sin{\left(1 \right)}}{4}\, d\theta$$$.
Lösung
Wende die Konstantenfaktorregel $$$\int c f{\left(\theta \right)}\, d\theta = c \int f{\left(\theta \right)}\, d\theta$$$ mit $$$c=\frac{\sin{\left(1 \right)}}{4}$$$ und $$$f{\left(\theta \right)} = \theta$$$ an:
$${\color{red}{\int{\frac{\theta \sin{\left(1 \right)}}{4} d \theta}}} = {\color{red}{\left(\frac{\sin{\left(1 \right)} \int{\theta d \theta}}{4}\right)}}$$
Wenden Sie die Potenzregel $$$\int \theta^{n}\, d\theta = \frac{\theta^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ mit $$$n=1$$$ an:
$$\frac{\sin{\left(1 \right)} {\color{red}{\int{\theta d \theta}}}}{4}=\frac{\sin{\left(1 \right)} {\color{red}{\frac{\theta^{1 + 1}}{1 + 1}}}}{4}=\frac{\sin{\left(1 \right)} {\color{red}{\left(\frac{\theta^{2}}{2}\right)}}}{4}$$
Daher,
$$\int{\frac{\theta \sin{\left(1 \right)}}{4} d \theta} = \frac{\theta^{2} \sin{\left(1 \right)}}{8}$$
Fügen Sie die Integrationskonstante hinzu:
$$\int{\frac{\theta \sin{\left(1 \right)}}{4} d \theta} = \frac{\theta^{2} \sin{\left(1 \right)}}{8}+C$$
Antwort
$$$\int \frac{\theta \sin{\left(1 \right)}}{4}\, d\theta = \frac{\theta^{2} \sin{\left(1 \right)}}{8} + C$$$A