Integral von $$$\sin^{2}{\left(x \right)} \cos^{3}{\left(3 x \right)}$$$

Bestimme $$$\int \sin^{2}{\left(x \right)} \cos^{3}{\left(3 x \right)}\, dx$$$.

Wende die Potenzreduktionsformel $$$\sin^{2}{\left(\alpha \right)} = \frac{1}{2} - \frac{\cos{\left(2 \alpha \right)}}{2}$$$ mit $$$\alpha=x$$$ an:

$${\color{red}{\int{\sin^{2}{\left(x \right)} \cos^{3}{\left(3 x \right)} d x}}} = {\color{red}{\int{\frac{\left(1 - \cos{\left(2 x \right)}\right) \cos^{3}{\left(3 x \right)}}{2} d x}}}$$

Wende die Potenzreduktionsformel $$$\cos^{3}{\left(\alpha \right)} = \frac{3 \cos{\left(\alpha \right)}}{4} + \frac{\cos{\left(3 \alpha \right)}}{4}$$$ mit $$$\alpha=3 x$$$ an:

$${\color{red}{\int{\frac{\left(1 - \cos{\left(2 x \right)}\right) \cos^{3}{\left(3 x \right)}}{2} d x}}} = {\color{red}{\int{\frac{\left(1 - \cos{\left(2 x \right)}\right) \left(3 \cos{\left(3 x \right)} + \cos{\left(9 x \right)}\right)}{8} d x}}}$$

Wende die Konstantenfaktorregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ mit $$$c=\frac{1}{8}$$$ und $$$f{\left(x \right)} = \left(1 - \cos{\left(2 x \right)}\right) \left(3 \cos{\left(3 x \right)} + \cos{\left(9 x \right)}\right)$$$ an:

$${\color{red}{\int{\frac{\left(1 - \cos{\left(2 x \right)}\right) \left(3 \cos{\left(3 x \right)} + \cos{\left(9 x \right)}\right)}{8} d x}}} = {\color{red}{\left(\frac{\int{\left(1 - \cos{\left(2 x \right)}\right) \left(3 \cos{\left(3 x \right)} + \cos{\left(9 x \right)}\right) d x}}{8}\right)}}$$

Expand the expression:

$$\frac{{\color{red}{\int{\left(1 - \cos{\left(2 x \right)}\right) \left(3 \cos{\left(3 x \right)} + \cos{\left(9 x \right)}\right) d x}}}}{8} = \frac{{\color{red}{\int{\left(- 3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} - \cos{\left(2 x \right)} \cos{\left(9 x \right)} + 3 \cos{\left(3 x \right)} + \cos{\left(9 x \right)}\right)d x}}}}{8}$$

Gliedweise integrieren:

$$\frac{{\color{red}{\int{\left(- 3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} - \cos{\left(2 x \right)} \cos{\left(9 x \right)} + 3 \cos{\left(3 x \right)} + \cos{\left(9 x \right)}\right)d x}}}}{8} = \frac{{\color{red}{\left(- \int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x} - \int{\cos{\left(2 x \right)} \cos{\left(9 x \right)} d x} + \int{3 \cos{\left(3 x \right)} d x} + \int{\cos{\left(9 x \right)} d x}\right)}}}{8}$$

Wende die Konstantenfaktorregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ mit $$$c=3$$$ und $$$f{\left(x \right)} = \cos{\left(3 x \right)}$$$ an:

$$- \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} - \frac{\int{\cos{\left(2 x \right)} \cos{\left(9 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} + \frac{{\color{red}{\int{3 \cos{\left(3 x \right)} d x}}}}{8} = - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} - \frac{\int{\cos{\left(2 x \right)} \cos{\left(9 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} + \frac{{\color{red}{\left(3 \int{\cos{\left(3 x \right)} d x}\right)}}}{8}$$

Sei $$$u=3 x$$$.

Dann $$$du=\left(3 x\right)^{\prime }dx = 3 dx$$$ (die Schritte sind » zu sehen), und es gilt $$$dx = \frac{du}{3}$$$.

Das Integral lässt sich umschreiben als

$$- \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} - \frac{\int{\cos{\left(2 x \right)} \cos{\left(9 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} + \frac{3 {\color{red}{\int{\cos{\left(3 x \right)} d x}}}}{8} = - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} - \frac{\int{\cos{\left(2 x \right)} \cos{\left(9 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} + \frac{3 {\color{red}{\int{\frac{\cos{\left(u \right)}}{3} d u}}}}{8}$$

Wende die Konstantenfaktorregel $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ mit $$$c=\frac{1}{3}$$$ und $$$f{\left(u \right)} = \cos{\left(u \right)}$$$ an:

$$- \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} - \frac{\int{\cos{\left(2 x \right)} \cos{\left(9 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} + \frac{3 {\color{red}{\int{\frac{\cos{\left(u \right)}}{3} d u}}}}{8} = - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} - \frac{\int{\cos{\left(2 x \right)} \cos{\left(9 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} + \frac{3 {\color{red}{\left(\frac{\int{\cos{\left(u \right)} d u}}{3}\right)}}}{8}$$

Das Integral des Kosinus ist $$$\int{\cos{\left(u \right)} d u} = \sin{\left(u \right)}$$$:

$$- \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} - \frac{\int{\cos{\left(2 x \right)} \cos{\left(9 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} + \frac{{\color{red}{\int{\cos{\left(u \right)} d u}}}}{8} = - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} - \frac{\int{\cos{\left(2 x \right)} \cos{\left(9 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} + \frac{{\color{red}{\sin{\left(u \right)}}}}{8}$$

Zur Erinnerung: $$$u=3 x$$$:

$$- \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} - \frac{\int{\cos{\left(2 x \right)} \cos{\left(9 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} + \frac{\sin{\left({\color{red}{u}} \right)}}{8} = - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} - \frac{\int{\cos{\left(2 x \right)} \cos{\left(9 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} + \frac{\sin{\left({\color{red}{\left(3 x\right)}} \right)}}{8}$$

Schreiben Sie den Integranden mithilfe der Formel $$$\cos\left(\alpha \right)\cos\left(\beta \right)=\frac{1}{2} \cos\left(\alpha-\beta \right)+\frac{1}{2} \cos\left(\alpha+\beta \right)$$$ mit $$$\alpha=2 x$$$ und $$$\beta=9 x$$$ um.:

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\int{\cos{\left(2 x \right)} \cos{\left(9 x \right)} d x}}}}{8} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\int{\left(\frac{\cos{\left(7 x \right)}}{2} + \frac{\cos{\left(11 x \right)}}{2}\right)d x}}}}{8}$$

Wende die Konstantenfaktorregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ mit $$$c=\frac{1}{2}$$$ und $$$f{\left(x \right)} = \cos{\left(7 x \right)} + \cos{\left(11 x \right)}$$$ an:

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\int{\left(\frac{\cos{\left(7 x \right)}}{2} + \frac{\cos{\left(11 x \right)}}{2}\right)d x}}}}{8} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\left(\frac{\int{\left(\cos{\left(7 x \right)} + \cos{\left(11 x \right)}\right)d x}}{2}\right)}}}{8}$$

Gliedweise integrieren:

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\int{\left(\cos{\left(7 x \right)} + \cos{\left(11 x \right)}\right)d x}}}}{16} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\left(\int{\cos{\left(7 x \right)} d x} + \int{\cos{\left(11 x \right)} d x}\right)}}}{16}$$

Sei $$$u=7 x$$$.

Dann $$$du=\left(7 x\right)^{\prime }dx = 7 dx$$$ (die Schritte sind » zu sehen), und es gilt $$$dx = \frac{du}{7}$$$.

Das Integral wird zu

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{\int{\cos{\left(11 x \right)} d x}}{16} - \frac{{\color{red}{\int{\cos{\left(7 x \right)} d x}}}}{16} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{\int{\cos{\left(11 x \right)} d x}}{16} - \frac{{\color{red}{\int{\frac{\cos{\left(u \right)}}{7} d u}}}}{16}$$

Wende die Konstantenfaktorregel $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ mit $$$c=\frac{1}{7}$$$ und $$$f{\left(u \right)} = \cos{\left(u \right)}$$$ an:

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{\int{\cos{\left(11 x \right)} d x}}{16} - \frac{{\color{red}{\int{\frac{\cos{\left(u \right)}}{7} d u}}}}{16} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{\int{\cos{\left(11 x \right)} d x}}{16} - \frac{{\color{red}{\left(\frac{\int{\cos{\left(u \right)} d u}}{7}\right)}}}{16}$$

Das Integral des Kosinus ist $$$\int{\cos{\left(u \right)} d u} = \sin{\left(u \right)}$$$:

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{\int{\cos{\left(11 x \right)} d x}}{16} - \frac{{\color{red}{\int{\cos{\left(u \right)} d u}}}}{112} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{\int{\cos{\left(11 x \right)} d x}}{16} - \frac{{\color{red}{\sin{\left(u \right)}}}}{112}$$

Zur Erinnerung: $$$u=7 x$$$:

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{\int{\cos{\left(11 x \right)} d x}}{16} - \frac{\sin{\left({\color{red}{u}} \right)}}{112} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{\int{\cos{\left(11 x \right)} d x}}{16} - \frac{\sin{\left({\color{red}{\left(7 x\right)}} \right)}}{112}$$

Sei $$$u=11 x$$$.

Dann $$$du=\left(11 x\right)^{\prime }dx = 11 dx$$$ (die Schritte sind » zu sehen), und es gilt $$$dx = \frac{du}{11}$$$.

Also,

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\int{\cos{\left(11 x \right)} d x}}}}{16} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\int{\frac{\cos{\left(u \right)}}{11} d u}}}}{16}$$

Wende die Konstantenfaktorregel $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ mit $$$c=\frac{1}{11}$$$ und $$$f{\left(u \right)} = \cos{\left(u \right)}$$$ an:

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\int{\frac{\cos{\left(u \right)}}{11} d u}}}}{16} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\left(\frac{\int{\cos{\left(u \right)} d u}}{11}\right)}}}{16}$$

Das Integral des Kosinus ist $$$\int{\cos{\left(u \right)} d u} = \sin{\left(u \right)}$$$:

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\int{\cos{\left(u \right)} d u}}}}{176} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\sin{\left(u \right)}}}}{176}$$

Zur Erinnerung: $$$u=11 x$$$:

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{\sin{\left({\color{red}{u}} \right)}}{176} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}{8} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{\sin{\left({\color{red}{\left(11 x\right)}} \right)}}{176}$$

Schreibe $$$\cos\left(2 x \right)\cos\left(3 x \right)$$$ mithilfe der Formel $$$\cos\left(\alpha \right)\cos\left(\beta \right)=\frac{1}{2} \cos\left(\alpha-\beta \right)+\frac{1}{2} \cos\left(\alpha+\beta \right)$$$ mit $$$\alpha=2 x$$$ und $$$\beta=3 x$$$ um:

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\int{3 \cos{\left(2 x \right)} \cos{\left(3 x \right)} d x}}}}{8} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\int{\left(\frac{3 \cos{\left(x \right)}}{2} + \frac{3 \cos{\left(5 x \right)}}{2}\right)d x}}}}{8}$$

Wende die Konstantenfaktorregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ mit $$$c=\frac{1}{2}$$$ und $$$f{\left(x \right)} = 3 \cos{\left(x \right)} + 3 \cos{\left(5 x \right)}$$$ an:

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\int{\left(\frac{3 \cos{\left(x \right)}}{2} + \frac{3 \cos{\left(5 x \right)}}{2}\right)d x}}}}{8} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\left(\frac{\int{\left(3 \cos{\left(x \right)} + 3 \cos{\left(5 x \right)}\right)d x}}{2}\right)}}}{8}$$

Gliedweise integrieren:

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\int{\left(3 \cos{\left(x \right)} + 3 \cos{\left(5 x \right)}\right)d x}}}}{16} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\left(\int{3 \cos{\left(x \right)} d x} + \int{3 \cos{\left(5 x \right)} d x}\right)}}}{16}$$

Wende die Konstantenfaktorregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ mit $$$c=3$$$ und $$$f{\left(x \right)} = \cos{\left(x \right)}$$$ an:

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} - \frac{\int{3 \cos{\left(5 x \right)} d x}}{16} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\int{3 \cos{\left(x \right)} d x}}}}{16} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} - \frac{\int{3 \cos{\left(5 x \right)} d x}}{16} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\left(3 \int{\cos{\left(x \right)} d x}\right)}}}{16}$$

Das Integral des Kosinus ist $$$\int{\cos{\left(x \right)} d x} = \sin{\left(x \right)}$$$:

$$\frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} - \frac{\int{3 \cos{\left(5 x \right)} d x}}{16} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{3 {\color{red}{\int{\cos{\left(x \right)} d x}}}}{16} = \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} - \frac{\int{3 \cos{\left(5 x \right)} d x}}{16} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{3 {\color{red}{\sin{\left(x \right)}}}}{16}$$

Wende die Konstantenfaktorregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ mit $$$c=3$$$ und $$$f{\left(x \right)} = \cos{\left(5 x \right)}$$$ an:

$$- \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\int{3 \cos{\left(5 x \right)} d x}}}}{16} = - \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{{\color{red}{\left(3 \int{\cos{\left(5 x \right)} d x}\right)}}}{16}$$

Sei $$$u=5 x$$$.

Dann $$$du=\left(5 x\right)^{\prime }dx = 5 dx$$$ (die Schritte sind » zu sehen), und es gilt $$$dx = \frac{du}{5}$$$.

Das Integral wird zu

$$- \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{3 {\color{red}{\int{\cos{\left(5 x \right)} d x}}}}{16} = - \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{3 {\color{red}{\int{\frac{\cos{\left(u \right)}}{5} d u}}}}{16}$$

Wende die Konstantenfaktorregel $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ mit $$$c=\frac{1}{5}$$$ und $$$f{\left(u \right)} = \cos{\left(u \right)}$$$ an:

$$- \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{3 {\color{red}{\int{\frac{\cos{\left(u \right)}}{5} d u}}}}{16} = - \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{3 {\color{red}{\left(\frac{\int{\cos{\left(u \right)} d u}}{5}\right)}}}{16}$$

Das Integral des Kosinus ist $$$\int{\cos{\left(u \right)} d u} = \sin{\left(u \right)}$$$:

$$- \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{3 {\color{red}{\int{\cos{\left(u \right)} d u}}}}{80} = - \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{3 {\color{red}{\sin{\left(u \right)}}}}{80}$$

Zur Erinnerung: $$$u=5 x$$$:

$$- \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{3 \sin{\left({\color{red}{u}} \right)}}{80} = - \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\int{\cos{\left(9 x \right)} d x}}{8} - \frac{3 \sin{\left({\color{red}{\left(5 x\right)}} \right)}}{80}$$

Sei $$$u=9 x$$$.

Dann $$$du=\left(9 x\right)^{\prime }dx = 9 dx$$$ (die Schritte sind » zu sehen), und es gilt $$$dx = \frac{du}{9}$$$.

Das Integral wird zu

$$- \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{3 \sin{\left(5 x \right)}}{80} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{{\color{red}{\int{\cos{\left(9 x \right)} d x}}}}{8} = - \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{3 \sin{\left(5 x \right)}}{80} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{{\color{red}{\int{\frac{\cos{\left(u \right)}}{9} d u}}}}{8}$$

Wende die Konstantenfaktorregel $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ mit $$$c=\frac{1}{9}$$$ und $$$f{\left(u \right)} = \cos{\left(u \right)}$$$ an:

$$- \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{3 \sin{\left(5 x \right)}}{80} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{{\color{red}{\int{\frac{\cos{\left(u \right)}}{9} d u}}}}{8} = - \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{3 \sin{\left(5 x \right)}}{80} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{{\color{red}{\left(\frac{\int{\cos{\left(u \right)} d u}}{9}\right)}}}{8}$$

Das Integral des Kosinus ist $$$\int{\cos{\left(u \right)} d u} = \sin{\left(u \right)}$$$:

$$- \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{3 \sin{\left(5 x \right)}}{80} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{{\color{red}{\int{\cos{\left(u \right)} d u}}}}{72} = - \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{3 \sin{\left(5 x \right)}}{80} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{{\color{red}{\sin{\left(u \right)}}}}{72}$$

Zur Erinnerung: $$$u=9 x$$$:

$$- \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{3 \sin{\left(5 x \right)}}{80} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\sin{\left({\color{red}{u}} \right)}}{72} = - \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{3 \sin{\left(5 x \right)}}{80} - \frac{\sin{\left(7 x \right)}}{112} - \frac{\sin{\left(11 x \right)}}{176} + \frac{\sin{\left({\color{red}{\left(9 x\right)}} \right)}}{72}$$

Daher,

$$\int{\sin^{2}{\left(x \right)} \cos^{3}{\left(3 x \right)} d x} = - \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{3 \sin{\left(5 x \right)}}{80} - \frac{\sin{\left(7 x \right)}}{112} + \frac{\sin{\left(9 x \right)}}{72} - \frac{\sin{\left(11 x \right)}}{176}$$

Fügen Sie die Integrationskonstante hinzu:

$$\int{\sin^{2}{\left(x \right)} \cos^{3}{\left(3 x \right)} d x} = - \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{3 \sin{\left(5 x \right)}}{80} - \frac{\sin{\left(7 x \right)}}{112} + \frac{\sin{\left(9 x \right)}}{72} - \frac{\sin{\left(11 x \right)}}{176}+C$$

$$$\int \sin^{2}{\left(x \right)} \cos^{3}{\left(3 x \right)}\, dx = \left(- \frac{3 \sin{\left(x \right)}}{16} + \frac{\sin{\left(3 x \right)}}{8} - \frac{3 \sin{\left(5 x \right)}}{80} - \frac{\sin{\left(7 x \right)}}{112} + \frac{\sin{\left(9 x \right)}}{72} - \frac{\sin{\left(11 x \right)}}{176}\right) + C$$$A