Integral von $$$\frac{\sec^{2}{\left(x \right)}}{2}$$$

Bestimme $$$\int \frac{\sec^{2}{\left(x \right)}}{2}\, dx$$$.

Wende die Konstantenfaktorregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ mit $$$c=\frac{1}{2}$$$ und $$$f{\left(x \right)} = \sec^{2}{\left(x \right)}$$$ an:

$${\color{red}{\int{\frac{\sec^{2}{\left(x \right)}}{2} d x}}} = {\color{red}{\left(\frac{\int{\sec^{2}{\left(x \right)} d x}}{2}\right)}}$$

Das Integral von $$$\sec^{2}{\left(x \right)}$$$ ist $$$\int{\sec^{2}{\left(x \right)} d x} = \tan{\left(x \right)}$$$:

$$\frac{{\color{red}{\int{\sec^{2}{\left(x \right)} d x}}}}{2} = \frac{{\color{red}{\tan{\left(x \right)}}}}{2}$$

Daher,

$$\int{\frac{\sec^{2}{\left(x \right)}}{2} d x} = \frac{\tan{\left(x \right)}}{2}$$

Fügen Sie die Integrationskonstante hinzu:

$$\int{\frac{\sec^{2}{\left(x \right)}}{2} d x} = \frac{\tan{\left(x \right)}}{2}+C$$

$$$\int \frac{\sec^{2}{\left(x \right)}}{2}\, dx = \frac{\tan{\left(x \right)}}{2} + C$$$A