Integral von $$$\frac{\ln\left(x\right)}{x^{9}}$$$

Bestimme $$$\int \frac{\ln\left(x\right)}{x^{9}}\, dx$$$.

Für das Integral $$$\int{\frac{\ln{\left(x \right)}}{x^{9}} d x}$$$ verwenden Sie die partielle Integration $$$\int \operatorname{u} \operatorname{dv} = \operatorname{u}\operatorname{v} - \int \operatorname{v} \operatorname{du}$$$.

Seien $$$\operatorname{u}=\ln{\left(x \right)}$$$ und $$$\operatorname{dv}=\frac{dx}{x^{9}}$$$.

Dann gilt $$$\operatorname{du}=\left(\ln{\left(x \right)}\right)^{\prime }dx=\frac{dx}{x}$$$ (Rechenschritte siehe ») und $$$\operatorname{v}=\int{\frac{1}{x^{9}} d x}=- \frac{1}{8 x^{8}}$$$ (Rechenschritte siehe »).

Das Integral wird zu

$${\color{red}{\int{\frac{\ln{\left(x \right)}}{x^{9}} d x}}}={\color{red}{\left(\ln{\left(x \right)} \cdot \left(- \frac{1}{8 x^{8}}\right)-\int{\left(- \frac{1}{8 x^{8}}\right) \cdot \frac{1}{x} d x}\right)}}={\color{red}{\left(- \int{\left(- \frac{1}{8 x^{9}}\right)d x} - \frac{\ln{\left(x \right)}}{8 x^{8}}\right)}}$$

Wende die Konstantenfaktorregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ mit $$$c=- \frac{1}{8}$$$ und $$$f{\left(x \right)} = \frac{1}{x^{9}}$$$ an:

$$- {\color{red}{\int{\left(- \frac{1}{8 x^{9}}\right)d x}}} - \frac{\ln{\left(x \right)}}{8 x^{8}} = - {\color{red}{\left(- \frac{\int{\frac{1}{x^{9}} d x}}{8}\right)}} - \frac{\ln{\left(x \right)}}{8 x^{8}}$$

Wenden Sie die Potenzregel $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ mit $$$n=-9$$$ an:

$$\frac{{\color{red}{\int{\frac{1}{x^{9}} d x}}}}{8} - \frac{\ln{\left(x \right)}}{8 x^{8}}=\frac{{\color{red}{\int{x^{-9} d x}}}}{8} - \frac{\ln{\left(x \right)}}{8 x^{8}}=\frac{{\color{red}{\frac{x^{-9 + 1}}{-9 + 1}}}}{8} - \frac{\ln{\left(x \right)}}{8 x^{8}}=\frac{{\color{red}{\left(- \frac{x^{-8}}{8}\right)}}}{8} - \frac{\ln{\left(x \right)}}{8 x^{8}}=\frac{{\color{red}{\left(- \frac{1}{8 x^{8}}\right)}}}{8} - \frac{\ln{\left(x \right)}}{8 x^{8}}$$

Daher,

$$\int{\frac{\ln{\left(x \right)}}{x^{9}} d x} = - \frac{\ln{\left(x \right)}}{8 x^{8}} - \frac{1}{64 x^{8}}$$

Vereinfachen:

$$\int{\frac{\ln{\left(x \right)}}{x^{9}} d x} = \frac{- 8 \ln{\left(x \right)} - 1}{64 x^{8}}$$

Fügen Sie die Integrationskonstante hinzu:

$$\int{\frac{\ln{\left(x \right)}}{x^{9}} d x} = \frac{- 8 \ln{\left(x \right)} - 1}{64 x^{8}}+C$$

$$$\int \frac{\ln\left(x\right)}{x^{9}}\, dx = \frac{- 8 \ln\left(x\right) - 1}{64 x^{8}} + C$$$A