Integral von $$$\frac{r}{a e^{2}}$$$ nach $$$a$$$

Bestimme $$$\int \frac{r}{a e^{2}}\, da$$$.

Wende die Konstantenfaktorregel $$$\int c f{\left(a \right)}\, da = c \int f{\left(a \right)}\, da$$$ mit $$$c=\frac{r}{e^{2}}$$$ und $$$f{\left(a \right)} = \frac{1}{a}$$$ an:

$${\color{red}{\int{\frac{r}{a e^{2}} d a}}} = {\color{red}{\frac{r \int{\frac{1}{a} d a}}{e^{2}}}}$$

Das Integral von $$$\frac{1}{a}$$$ ist $$$\int{\frac{1}{a} d a} = \ln{\left(\left|{a}\right| \right)}$$$:

$$\frac{r {\color{red}{\int{\frac{1}{a} d a}}}}{e^{2}} = \frac{r {\color{red}{\ln{\left(\left|{a}\right| \right)}}}}{e^{2}}$$

Daher,

$$\int{\frac{r}{a e^{2}} d a} = \frac{r \ln{\left(\left|{a}\right| \right)}}{e^{2}}$$

Fügen Sie die Integrationskonstante hinzu:

$$\int{\frac{r}{a e^{2}} d a} = \frac{r \ln{\left(\left|{a}\right| \right)}}{e^{2}}+C$$

$$$\int \frac{r}{a e^{2}}\, da = \frac{r \ln\left(\left|{a}\right|\right)}{e^{2}} + C$$$A