Integral von $$$\frac{- \sin^{2}{\left(x \right)} + \cos{\left(x \right)}}{\sin{\left(x \right)}}$$$
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Ihre Eingabe
Bestimme $$$\int \frac{- \sin^{2}{\left(x \right)} + \cos{\left(x \right)}}{\sin{\left(x \right)}}\, dx$$$.
Lösung
Expand the expression:
$${\color{red}{\int{\frac{- \sin^{2}{\left(x \right)} + \cos{\left(x \right)}}{\sin{\left(x \right)}} d x}}} = {\color{red}{\int{\left(- \sin{\left(x \right)} + \frac{\cos{\left(x \right)}}{\sin{\left(x \right)}}\right)d x}}}$$
Gliedweise integrieren:
$${\color{red}{\int{\left(- \sin{\left(x \right)} + \frac{\cos{\left(x \right)}}{\sin{\left(x \right)}}\right)d x}}} = {\color{red}{\left(\int{\frac{\cos{\left(x \right)}}{\sin{\left(x \right)}} d x} - \int{\sin{\left(x \right)} d x}\right)}}$$
Das Integral des Sinus lautet $$$\int{\sin{\left(x \right)} d x} = - \cos{\left(x \right)}$$$:
$$\int{\frac{\cos{\left(x \right)}}{\sin{\left(x \right)}} d x} - {\color{red}{\int{\sin{\left(x \right)} d x}}} = \int{\frac{\cos{\left(x \right)}}{\sin{\left(x \right)}} d x} - {\color{red}{\left(- \cos{\left(x \right)}\right)}}$$
Sei $$$u=\sin{\left(x \right)}$$$.
Dann $$$du=\left(\sin{\left(x \right)}\right)^{\prime }dx = \cos{\left(x \right)} dx$$$ (die Schritte sind » zu sehen), und es gilt $$$\cos{\left(x \right)} dx = du$$$.
Somit,
$$\cos{\left(x \right)} + {\color{red}{\int{\frac{\cos{\left(x \right)}}{\sin{\left(x \right)}} d x}}} = \cos{\left(x \right)} + {\color{red}{\int{\frac{1}{u} d u}}}$$
Das Integral von $$$\frac{1}{u}$$$ ist $$$\int{\frac{1}{u} d u} = \ln{\left(\left|{u}\right| \right)}$$$:
$$\cos{\left(x \right)} + {\color{red}{\int{\frac{1}{u} d u}}} = \cos{\left(x \right)} + {\color{red}{\ln{\left(\left|{u}\right| \right)}}}$$
Zur Erinnerung: $$$u=\sin{\left(x \right)}$$$:
$$\ln{\left(\left|{{\color{red}{u}}}\right| \right)} + \cos{\left(x \right)} = \ln{\left(\left|{{\color{red}{\sin{\left(x \right)}}}}\right| \right)} + \cos{\left(x \right)}$$
Daher,
$$\int{\frac{- \sin^{2}{\left(x \right)} + \cos{\left(x \right)}}{\sin{\left(x \right)}} d x} = \ln{\left(\left|{\sin{\left(x \right)}}\right| \right)} + \cos{\left(x \right)}$$
Fügen Sie die Integrationskonstante hinzu:
$$\int{\frac{- \sin^{2}{\left(x \right)} + \cos{\left(x \right)}}{\sin{\left(x \right)}} d x} = \ln{\left(\left|{\sin{\left(x \right)}}\right| \right)} + \cos{\left(x \right)}+C$$
Antwort
$$$\int \frac{- \sin^{2}{\left(x \right)} + \cos{\left(x \right)}}{\sin{\left(x \right)}}\, dx = \left(\ln\left(\left|{\sin{\left(x \right)}}\right|\right) + \cos{\left(x \right)}\right) + C$$$A