Integral von $$$\frac{2 - 3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}}$$$
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Ihre Eingabe
Bestimme $$$\int \frac{2 - 3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}}\, dx$$$.
Lösung
Expand the expression:
$${\color{red}{\int{\frac{2 - 3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x}}} = {\color{red}{\int{\left(- \frac{3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} + \frac{2}{\cos^{2}{\left(x \right)}}\right)d x}}}$$
Gliedweise integrieren:
$${\color{red}{\int{\left(- \frac{3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} + \frac{2}{\cos^{2}{\left(x \right)}}\right)d x}}} = {\color{red}{\left(- \int{\frac{3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x} + \int{\frac{2}{\cos^{2}{\left(x \right)}} d x}\right)}}$$
Wende die Konstantenfaktorregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ mit $$$c=2$$$ und $$$f{\left(x \right)} = \frac{1}{\cos^{2}{\left(x \right)}}$$$ an:
$$- \int{\frac{3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x} + {\color{red}{\int{\frac{2}{\cos^{2}{\left(x \right)}} d x}}} = - \int{\frac{3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x} + {\color{red}{\left(2 \int{\frac{1}{\cos^{2}{\left(x \right)}} d x}\right)}}$$
Schreibe den Integranden in Abhängigkeit von der Sekans um:
$$- \int{\frac{3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x} + 2 {\color{red}{\int{\frac{1}{\cos^{2}{\left(x \right)}} d x}}} = - \int{\frac{3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x} + 2 {\color{red}{\int{\sec^{2}{\left(x \right)} d x}}}$$
Das Integral von $$$\sec^{2}{\left(x \right)}$$$ ist $$$\int{\sec^{2}{\left(x \right)} d x} = \tan{\left(x \right)}$$$:
$$- \int{\frac{3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x} + 2 {\color{red}{\int{\sec^{2}{\left(x \right)} d x}}} = - \int{\frac{3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x} + 2 {\color{red}{\tan{\left(x \right)}}}$$
Wende die Konstantenfaktorregel $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$ mit $$$c=3$$$ und $$$f{\left(x \right)} = \frac{\sin{\left(x \right)}}{\cos^{2}{\left(x \right)}}$$$ an:
$$2 \tan{\left(x \right)} - {\color{red}{\int{\frac{3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x}}} = 2 \tan{\left(x \right)} - {\color{red}{\left(3 \int{\frac{\sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x}\right)}}$$
Sei $$$u=\cos{\left(x \right)}$$$.
Dann $$$du=\left(\cos{\left(x \right)}\right)^{\prime }dx = - \sin{\left(x \right)} dx$$$ (die Schritte sind » zu sehen), und es gilt $$$\sin{\left(x \right)} dx = - du$$$.
Das Integral wird zu
$$2 \tan{\left(x \right)} - 3 {\color{red}{\int{\frac{\sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x}}} = 2 \tan{\left(x \right)} - 3 {\color{red}{\int{\left(- \frac{1}{u^{2}}\right)d u}}}$$
Wende die Konstantenfaktorregel $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ mit $$$c=-1$$$ und $$$f{\left(u \right)} = \frac{1}{u^{2}}$$$ an:
$$2 \tan{\left(x \right)} - 3 {\color{red}{\int{\left(- \frac{1}{u^{2}}\right)d u}}} = 2 \tan{\left(x \right)} - 3 {\color{red}{\left(- \int{\frac{1}{u^{2}} d u}\right)}}$$
Wenden Sie die Potenzregel $$$\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ mit $$$n=-2$$$ an:
$$2 \tan{\left(x \right)} + 3 {\color{red}{\int{\frac{1}{u^{2}} d u}}}=2 \tan{\left(x \right)} + 3 {\color{red}{\int{u^{-2} d u}}}=2 \tan{\left(x \right)} + 3 {\color{red}{\frac{u^{-2 + 1}}{-2 + 1}}}=2 \tan{\left(x \right)} + 3 {\color{red}{\left(- u^{-1}\right)}}=2 \tan{\left(x \right)} + 3 {\color{red}{\left(- \frac{1}{u}\right)}}$$
Zur Erinnerung: $$$u=\cos{\left(x \right)}$$$:
$$2 \tan{\left(x \right)} - 3 {\color{red}{u}}^{-1} = 2 \tan{\left(x \right)} - 3 {\color{red}{\cos{\left(x \right)}}}^{-1}$$
Daher,
$$\int{\frac{2 - 3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x} = 2 \tan{\left(x \right)} - \frac{3}{\cos{\left(x \right)}}$$
Fügen Sie die Integrationskonstante hinzu:
$$\int{\frac{2 - 3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}} d x} = 2 \tan{\left(x \right)} - \frac{3}{\cos{\left(x \right)}}+C$$
Antwort
$$$\int \frac{2 - 3 \sin{\left(x \right)}}{\cos^{2}{\left(x \right)}}\, dx = \left(2 \tan{\left(x \right)} - \frac{3}{\cos{\left(x \right)}}\right) + C$$$A