Integral von $$$\left(1 - u^{2}\right)^{2}$$$

Bestimme $$$\int \left(1 - u^{2}\right)^{2}\, du$$$.

Expand the expression:

$${\color{red}{\int{\left(1 - u^{2}\right)^{2} d u}}} = {\color{red}{\int{\left(u^{4} - 2 u^{2} + 1\right)d u}}}$$

Gliedweise integrieren:

$${\color{red}{\int{\left(u^{4} - 2 u^{2} + 1\right)d u}}} = {\color{red}{\left(\int{1 d u} - \int{2 u^{2} d u} + \int{u^{4} d u}\right)}}$$

Wenden Sie die Konstantenregel $$$\int c\, du = c u$$$ mit $$$c=1$$$ an:

$$- \int{2 u^{2} d u} + \int{u^{4} d u} + {\color{red}{\int{1 d u}}} = - \int{2 u^{2} d u} + \int{u^{4} d u} + {\color{red}{u}}$$

Wenden Sie die Potenzregel $$$\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ mit $$$n=4$$$ an:

$$u - \int{2 u^{2} d u} + {\color{red}{\int{u^{4} d u}}}=u - \int{2 u^{2} d u} + {\color{red}{\frac{u^{1 + 4}}{1 + 4}}}=u - \int{2 u^{2} d u} + {\color{red}{\left(\frac{u^{5}}{5}\right)}}$$

Wende die Konstantenfaktorregel $$$\int c f{\left(u \right)}\, du = c \int f{\left(u \right)}\, du$$$ mit $$$c=2$$$ und $$$f{\left(u \right)} = u^{2}$$$ an:

$$\frac{u^{5}}{5} + u - {\color{red}{\int{2 u^{2} d u}}} = \frac{u^{5}}{5} + u - {\color{red}{\left(2 \int{u^{2} d u}\right)}}$$

Wenden Sie die Potenzregel $$$\int u^{n}\, du = \frac{u^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$ mit $$$n=2$$$ an:

$$\frac{u^{5}}{5} + u - 2 {\color{red}{\int{u^{2} d u}}}=\frac{u^{5}}{5} + u - 2 {\color{red}{\frac{u^{1 + 2}}{1 + 2}}}=\frac{u^{5}}{5} + u - 2 {\color{red}{\left(\frac{u^{3}}{3}\right)}}$$

Daher,

$$\int{\left(1 - u^{2}\right)^{2} d u} = \frac{u^{5}}{5} - \frac{2 u^{3}}{3} + u$$

Fügen Sie die Integrationskonstante hinzu:

$$\int{\left(1 - u^{2}\right)^{2} d u} = \frac{u^{5}}{5} - \frac{2 u^{3}}{3} + u+C$$

$$$\int \left(1 - u^{2}\right)^{2}\, du = \left(\frac{u^{5}}{5} - \frac{2 u^{3}}{3} + u\right) + C$$$A