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$$$\left[\begin{array}{cc}1 - \lambda & \frac{1}{5}\\\frac{1}{5} & 1 - \lambda\end{array}\right]$$$ 的行列式
相关计算器: 代数余子式矩阵计算器
您的输入
计算 $$$\left|\begin{array}{cc}1 - \lambda & \frac{1}{5}\\\frac{1}{5} & 1 - \lambda\end{array}\right|$$$。
解答
2x2 矩阵的行列式为 $$$\left|\begin{array}{cc}a & b\\c & d\end{array}\right| = a d - b c$$$。
$$$\left|\begin{array}{cc}1 - \lambda & \frac{1}{5}\\\frac{1}{5} & 1 - \lambda\end{array}\right| = \left(1 - \lambda\right)\cdot \left(1 - \lambda\right) - \left(\frac{1}{5}\right)\cdot \left(\frac{1}{5}\right) = \lambda^{2} - 2 \lambda + \frac{24}{25}$$$
答案
$$$\left|\begin{array}{cc}1 - \lambda & \frac{1}{5}\\\frac{1}{5} & 1 - \lambda\end{array}\right| = \lambda^{2} - 2 \lambda + \frac{24}{25} = \lambda^{2} - 2 \lambda + 0.96$$$A