$$$- \csc{\left(x \right)}$$$ 的积分

该计算器将求出$$$- \csc{\left(x \right)}$$$的积分/原函数,并显示步骤。

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您的输入

$$$\int \left(- \csc{\left(x \right)}\right)\, dx$$$

解答

$$$c=-1$$$$$$f{\left(x \right)} = \csc{\left(x \right)}$$$ 应用常数倍法则 $$$\int c f{\left(x \right)}\, dx = c \int f{\left(x \right)}\, dx$$$

$${\color{red}{\int{\left(- \csc{\left(x \right)}\right)d x}}} = {\color{red}{\left(- \int{\csc{\left(x \right)} d x}\right)}}$$

将余割改写为$$$\csc\left(x\right)=\frac{1}{\sin\left(x\right)}$$$:

$$- {\color{red}{\int{\csc{\left(x \right)} d x}}} = - {\color{red}{\int{\frac{1}{\sin{\left(x \right)}} d x}}}$$

使用二倍角公式 $$$\sin\left(x\right)=2\sin\left(\frac{x}{2}\right)\cos\left(\frac{x}{2}\right)$$$ 改写正弦:

$$- {\color{red}{\int{\frac{1}{\sin{\left(x \right)}} d x}}} = - {\color{red}{\int{\frac{1}{2 \sin{\left(\frac{x}{2} \right)} \cos{\left(\frac{x}{2} \right)}} d x}}}$$

将分子和分母同时乘以 $$$\sec^2\left(\frac{x}{2} \right)$$$:

$$- {\color{red}{\int{\frac{1}{2 \sin{\left(\frac{x}{2} \right)} \cos{\left(\frac{x}{2} \right)}} d x}}} = - {\color{red}{\int{\frac{\sec^{2}{\left(\frac{x}{2} \right)}}{2 \tan{\left(\frac{x}{2} \right)}} d x}}}$$

$$$u=\tan{\left(\frac{x}{2} \right)}$$$

$$$du=\left(\tan{\left(\frac{x}{2} \right)}\right)^{\prime }dx = \frac{\sec^{2}{\left(\frac{x}{2} \right)}}{2} dx$$$ (步骤见»),并有$$$\sec^{2}{\left(\frac{x}{2} \right)} dx = 2 du$$$

积分变为

$$- {\color{red}{\int{\frac{\sec^{2}{\left(\frac{x}{2} \right)}}{2 \tan{\left(\frac{x}{2} \right)}} d x}}} = - {\color{red}{\int{\frac{1}{u} d u}}}$$

$$$\frac{1}{u}$$$ 的积分为 $$$\int{\frac{1}{u} d u} = \ln{\left(\left|{u}\right| \right)}$$$:

$$- {\color{red}{\int{\frac{1}{u} d u}}} = - {\color{red}{\ln{\left(\left|{u}\right| \right)}}}$$

回忆一下 $$$u=\tan{\left(\frac{x}{2} \right)}$$$:

$$- \ln{\left(\left|{{\color{red}{u}}}\right| \right)} = - \ln{\left(\left|{{\color{red}{\tan{\left(\frac{x}{2} \right)}}}}\right| \right)}$$

因此,

$$\int{\left(- \csc{\left(x \right)}\right)d x} = - \ln{\left(\left|{\tan{\left(\frac{x}{2} \right)}}\right| \right)}$$

加上积分常数:

$$\int{\left(- \csc{\left(x \right)}\right)d x} = - \ln{\left(\left|{\tan{\left(\frac{x}{2} \right)}}\right| \right)}+C$$

答案

$$$\int \left(- \csc{\left(x \right)}\right)\, dx = - \ln\left(\left|{\tan{\left(\frac{x}{2} \right)}}\right|\right) + C$$$A


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