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$$$- x + \cos{\left(x \right)}$$$ 的积分
您的输入
求$$$\int \left(- x + \cos{\left(x \right)}\right)\, dx$$$。
解答
逐项积分：
$${\color{red}{\int{\left(- x + \cos{\left(x \right)}\right)d x}}} = {\color{red}{\left(- \int{x d x} + \int{\cos{\left(x \right)} d x}\right)}}$$
应用幂法则 $$$\int x^{n}\, dx = \frac{x^{n + 1}}{n + 1}$$$ $$$\left(n \neq -1 \right)$$$，其中 $$$n=1$$$：
$$\int{\cos{\left(x \right)} d x} - {\color{red}{\int{x d x}}}=\int{\cos{\left(x \right)} d x} - {\color{red}{\frac{x^{1 + 1}}{1 + 1}}}=\int{\cos{\left(x \right)} d x} - {\color{red}{\left(\frac{x^{2}}{2}\right)}}$$
余弦函数的积分为 $$$\int{\cos{\left(x \right)} d x} = \sin{\left(x \right)}$$$：
$$- \frac{x^{2}}{2} + {\color{red}{\int{\cos{\left(x \right)} d x}}} = - \frac{x^{2}}{2} + {\color{red}{\sin{\left(x \right)}}}$$
因此，
$$\int{\left(- x + \cos{\left(x \right)}\right)d x} = - \frac{x^{2}}{2} + \sin{\left(x \right)}$$
加上积分常数：
$$\int{\left(- x + \cos{\left(x \right)}\right)d x} = - \frac{x^{2}}{2} + \sin{\left(x \right)}+C$$
答案
$$$\int \left(- x + \cos{\left(x \right)}\right)\, dx = \left(- \frac{x^{2}}{2} + \sin{\left(x \right)}\right) + C$$$A