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$$$x^{3} - 5$$$的导数
您的输入
求$$$\frac{d}{dx} \left(x^{3} - 5\right)$$$。
解答
和/差的导数等于导数的和/差：
$${\color{red}\left(\frac{d}{dx} \left(x^{3} - 5\right)\right)} = {\color{red}\left(\frac{d}{dx} \left(x^{3}\right) - \frac{d}{dx} \left(5\right)\right)}$$应用幂次法则 $$$\frac{d}{dx} \left(x^{n}\right) = n x^{n - 1}$$$，其中 $$$n = 3$$$:
$${\color{red}\left(\frac{d}{dx} \left(x^{3}\right)\right)} - \frac{d}{dx} \left(5\right) = {\color{red}\left(3 x^{2}\right)} - \frac{d}{dx} \left(5\right)$$常数的导数是$$$0$$$:
$$3 x^{2} - {\color{red}\left(\frac{d}{dx} \left(5\right)\right)} = 3 x^{2} - {\color{red}\left(0\right)}$$因此，$$$\frac{d}{dx} \left(x^{3} - 5\right) = 3 x^{2}$$$。
答案
$$$\frac{d}{dx} \left(x^{3} - 5\right) = 3 x^{2}$$$A
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