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$$$t - 1$$$的导数
您的输入
求$$$\frac{d}{dt} \left(t - 1\right)$$$。
解答
和/差的导数等于导数的和/差：
$${\color{red}\left(\frac{d}{dt} \left(t - 1\right)\right)} = {\color{red}\left(\frac{d}{dt} \left(t\right) - \frac{d}{dt} \left(1\right)\right)}$$常数的导数是$$$0$$$:
$$- {\color{red}\left(\frac{d}{dt} \left(1\right)\right)} + \frac{d}{dt} \left(t\right) = - {\color{red}\left(0\right)} + \frac{d}{dt} \left(t\right)$$应用幂法则 $$$\frac{d}{dt} \left(t^{n}\right) = n t^{n - 1}$$$，取 $$$n = 1$$$，也就是说，$$$\frac{d}{dt} \left(t\right) = 1$$$：
$${\color{red}\left(\frac{d}{dt} \left(t\right)\right)} = {\color{red}\left(1\right)}$$因此，$$$\frac{d}{dt} \left(t - 1\right) = 1$$$。
答案
$$$\frac{d}{dt} \left(t - 1\right) = 1$$$A
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