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$$$\sec^{3}{\left(x \right)}$$$的导数
您的输入
求$$$\frac{d}{dx} \left(\sec^{3}{\left(x \right)}\right)$$$。
解答
函数$$$\sec^{3}{\left(x \right)}$$$是两个函数$$$f{\left(u \right)} = u^{3}$$$和$$$g{\left(x \right)} = \sec{\left(x \right)}$$$的复合$$$f{\left(g{\left(x \right)} \right)}$$$。
应用链式法则 $$$\frac{d}{dx} \left(f{\left(g{\left(x \right)} \right)}\right) = \frac{d}{du} \left(f{\left(u \right)}\right) \frac{d}{dx} \left(g{\left(x \right)}\right)$$$：
$${\color{red}\left(\frac{d}{dx} \left(\sec^{3}{\left(x \right)}\right)\right)} = {\color{red}\left(\frac{d}{du} \left(u^{3}\right) \frac{d}{dx} \left(\sec{\left(x \right)}\right)\right)}$$应用幂次法则 $$$\frac{d}{du} \left(u^{n}\right) = n u^{n - 1}$$$，其中 $$$n = 3$$$:
$${\color{red}\left(\frac{d}{du} \left(u^{3}\right)\right)} \frac{d}{dx} \left(\sec{\left(x \right)}\right) = {\color{red}\left(3 u^{2}\right)} \frac{d}{dx} \left(\sec{\left(x \right)}\right)$$返回到原变量：
$$3 {\color{red}\left(u\right)}^{2} \frac{d}{dx} \left(\sec{\left(x \right)}\right) = 3 {\color{red}\left(\sec{\left(x \right)}\right)}^{2} \frac{d}{dx} \left(\sec{\left(x \right)}\right)$$正割函数的导数为 $$$\frac{d}{dx} \left(\sec{\left(x \right)}\right) = \tan{\left(x \right)} \sec{\left(x \right)}$$$：
$$3 \sec^{2}{\left(x \right)} {\color{red}\left(\frac{d}{dx} \left(\sec{\left(x \right)}\right)\right)} = 3 \sec^{2}{\left(x \right)} {\color{red}\left(\tan{\left(x \right)} \sec{\left(x \right)}\right)}$$因此，$$$\frac{d}{dx} \left(\sec^{3}{\left(x \right)}\right) = 3 \tan{\left(x \right)} \sec^{3}{\left(x \right)}$$$。
答案
$$$\frac{d}{dx} \left(\sec^{3}{\left(x \right)}\right) = 3 \tan{\left(x \right)} \sec^{3}{\left(x \right)}$$$A